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SOVA2 [1]
3 years ago
5

How many atoms are there in 2.43 g of mercury?

Chemistry
1 answer:
ArbitrLikvidat [17]3 years ago
8 0
Number of moles of mercury = \frac{weight of mercury}{molar mass of mercury} =  \frac{2.43}{200.59} = 0.012 moles. Number of atoms = moles of Hg x 6.02 x 10^23 = 0.012 x 6.02 x 10^23 = 7.224 x 10^21 atoms. Hope this helps!
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C3H8 + 5 O2 → 3 CO2 + 4 H2O
Nataly [62]

Answer:

¹/3 C3H8(g) + ⁵/3 O2(g)

Explanation:

The coefficient before every molecule is representative of the number of moles. We can represent it in ration form so as to calculate the question;

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(l) means;

For every 1 mole of C₃H₈(g) and 5 moles of  O₂(g) produces  3 moles of  CO₂(g) and 4 moles of H₂O(l).

Therefore to produce 1.00 mole of CO₂(g);

We represent it in ratio;

C₃H₈(g) : CO₂(g)

1  :     3

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