Question

How many atoms are there in 2.43 g of mercury?

Answer 1

Number of moles of mercury = $\frac{weight of mercury}{molar mass of mercury} = \frac{2.43}{200.59} = 0.012 moles$. Number of atoms = moles of Hg x 6.02 x 10^23 = 0.012 x 6.02 x 10^23 = 7.224 x 10^21 atoms. Hope this helps!