Answer:
Following are the explanation to this question:
Explanation:
The salts of carboxylate are named by the writing, which is also named as the creation of the first, which is followed by the name of the carboxylic acid were '-ic' of the acid end and replaced by the 'ate'.
Following are the description of the given reaction:
In reaction A:
2-Bromopropanoic acid= 
⇄ 
The IUPAC name is Sodium-2-Bromopropanate
In reaction B:
2-Methylhexanoic acid= 
⇄ 
The IUPAC name is Sodium-2-Methyl hexanoate
Answer: KOH + HBr = H2O + KBr
Explanation: hope this helps
Density = mass/volume = 60/0.7 = 85.71g
279 g * (1 mol/180.559g glucose) * (2 mol ethanol/1 mol glucose) * (46.068g ethanol/1mol) =
142 g ethanol produced
Based on the incomplete neutralization reaction above, the corresponding salts that each reaction would form are as follows:
1. H2SO4 + 2NH4OH----(NH4)2SO4 with water as a byproduct
2. 2NaOH + H2CO3 ----Na2CO3 with water as a byproduct
3. HNO3 + KOH ----KNO3 with water as a byproduct