Answer:
The unusual 
values for this model are: 
Step-by-step explanation:
A binomial random variable represents the number of successes obtained in a repetition of 
Bernoulli-type trials with probability of success 
. In this particular case, 
, and 
, therefore, the model is 
. So, you have:
The unusual values for this model are: 
Answer:
The probability is .034375 or 11/320
Step-by-step explanation:
the probability of a senior being chose first is 22 (seniors) divided my total number of students (80) is .275 percent.
multiplied by the probability of a sophomore being chosen 10/80 which equals .125.
multiply those together and you get your probability. 0.034375 or 11/320
Answer:
Step-by-step explanation:
![= (x +1 ) \cdot \frac{(2x - 1)^{\frac{3}{2}}}{3} - \int \frac{(2x - 1)^{\frac{3}{2}}}{3} dx \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ [ \ u = x + 1 => du = dx \ ]](https://tex.z-dn.net/?f=%3D%20%28x%20%2B1%20%29%20%5Ccdot%20%5Cfrac%7B%282x%20-%201%29%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%7D%7B3%7D%20-%20%5Cint%20%5Cfrac%7B%282x%20-%201%29%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%7D%7B3%7D%20dx%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%20%5B%20%5C%20u%20%3D%20x%20%2B%201%20%3D%3E%20du%20%3D%20dx%20%20%5C%20%5D)
x^3y^3 + 343
The way the sum of cubes works is by taking the roots of each term and applying the formula.
The sum of cubes is as follows:
a^3 + b^3 = (a + b)(a^2 - ab + b^2)
In this case, we would display it like this:
x^3y^3 + 343 = (xy + 7)(x^2y^2 - 7xy + 49)
