Answer:
number of moles of CO2 is 0.054
number of moles of CO is 0.107
number of moles of O2 remaining is 0.01 mole
mole fraction of CO is 0.63
Explanation:
Firstly, we write the equation of reaction;
3C(s) +2O2(g) → CO2(g) +2CO(g)
Now, we proceed.
From the written equation, we can deduce that
3 mol C = 2 mol O2 = 1 mol CO2 = 2 mol CO
No of mol of C reacted = 0.161 mol
limiting reactant according to the question is Carbon
a. no of mol of CO2 formed = 0.161*1/3 = 0.054 moles ( no of moles of CO2 formed is one-third of no of moles of carbon reacted. This is obtainable from their mole ratio 1:3)
b. no of mol of CO formed = 0.161*2/3 = 0.107 mol
c. no of mol of O2 remaining = 0.117 - (0.151*2/3) = 0.117-0.107 = 0.01 mole
d. mole fraction of CO = no of mol of CO/Total number of moles
= 0.107/(0.107+0.054+0.01)
= 0.625730994152 which is approximately 0.63
