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larisa86 [58]
3 years ago
11

A power drill runs at a voltage of 120 V and draws a current of 4 A. What is the wattage of the drill?

Chemistry
2 answers:
creativ13 [48]3 years ago
7 0
First this is not Chemistry..

And to answer this you need to know simple formula :)

Wattage = Voltage * Ampere

So the answer is 480 Wattage
Fofino [41]3 years ago
7 0
The answer is 480 wattage 
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To change an object from a liquid to a gas _________ must happen
nignag [31]
Evaporation!
-Melting is a solid to a liquid
-sublimation is directly from a solid to a gas
-condensation gas to liquid
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3 years ago
Why does sodium form a 1+ ion but magnesium forms a 2+ ion
NARA [144]
Because Na has one too many electron to be stable, while Mg has 2. once they loose those electrons, they will be come ion. loosing one electron will give the ion a 1+ charge, and loosing 2 will create a 2+ charge
6 0
3 years ago
What might happen if you got too close to the center of the Milky Way galaxy?
Lady_Fox [76]

Answer:

you would be trapped in the gravitational pull of a black hole

Explanation:

there is a black hole in the center of the galacy

5 0
3 years ago
How many moles of ions are released when 0.27 mole of cobalt chloride is dissolved in water?
egoroff_w [7]

0.81 moles

Explanation:

cobalt chloride when dissolved in water dissociate into cobalt and chloride ions as shown;

CoCl₂ (s) → [Co²⁺](aq) + 2[Cl⁻] (aq)

The mole ratio between CoCl₂ and [Co²⁺] is 1 ; 1 while the mole ratio between CoCl₂ and [Cl⁻] is 1 : 2

Therefore; 0.27 moles of CoCl₂ will form;

(1 * 0.27) = 0.27 moles of [Co²⁺] ions

(2 * 0.27) = 0.54 moles of [Cl⁻] ions

Total moles of dissociated ions are;

0.27 + 0.54

= 0.81 moles

4 0
3 years ago
Determine the oxidation number of Cl in each of the following species.Cl2O7AlCl4-Ba(ClO2)2CIF4+
DIA [1.3K]

These are four questons and four answers:

Answers:

  • 1)  7⁺
  • 2) 1⁻
  • 3) 3⁺
  • 4) 5⁺

Explanation:

<u><em>Question 1) </em></u><u><em>Cl₂O₇:</em></u>

a) Net charge of the compound: 0

b) Rule: oxygen works with oxidation state +2, except with peroxides.

d) Rule: balance of charges: ∑ of the charges = net charge

Call X the oxidation number of Cl:

  • 2×X + 7 (-2) = 0
  • 2X - 14 = 0
  • 2X = +14
  • X = +14 /2 = + 7

<em>Conclusion: the oxidation number of Cl in Cl₂O₇ is 7⁺.</em>

<u><em>Question 2) </em></u><u><em>AlCl₄⁻</em></u>

a) Net charge of the ion: - 1

b) Rule: common oxidation number of Al in compounds: +3

c) Rule: balance of charges: ∑ charges = net charge = - 1

  • 1 (+3) + 4X = - 1
  • +3 + 4X = - 1
  • 4X = - 1 - 3
  • 4X = - 4
  • X = - 1

<em>Conclusion: the oxidation number of Cl in AlCl₄⁻ is 1 ⁻.</em>

<em><u>Question 3)</u></em><em><u> Ba(ClO₂)₂</u></em>

a) Net charge of the compound: 0

b) Rule: common oxidation number of BA in compounds: +2

c) Rule: common oxidation number of O in compounds (except in peroxides): -2

d) Rule: balance of charges: ∑ charges = net charge = 0

  • +2 + 2X + 4 (-2) = 0
  • 2X +2 - 8 = 0
  • 2X - 6 = 0
  • 2X = +6
  • X = + 3

<em>Conclusion: the oxidation number of Cl in Ba(ClO₂)₂  is 3⁺.</em>

<u><em>Question 4)</em></u><u><em> CIF₄⁺</em></u>

a) Net charge of the ion: + 1

b) Rule: common oxidation number of F : - 1 (it is the most electronegative)

c) Rule: balance of charges: ∑ charges = net charge = + 1

  • X + 4(-1) = +1
  • X - 4 = +1
  • X = +1 + 4
  • X = + 5

<em>Conclusion: the oxidation number of Cl in ClF₄⁺ is 5⁺.</em>

6 0
3 years ago
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