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Cerrena [4.2K]
3 years ago
7

Find the value of x, rounded to the nearest tenth.

Mathematics
1 answer:
MissTica3 years ago
7 0

Answer:

x= 36.2

Step-by-step explanation:

Because that's a right triangle and the reference angle and adjacent side measures are given to us, we can use the trig ratio for cosine.  Cosine relates the side adjacent to (next to...NOT ever the hypotenuse!) the angle to the hypotenuse.  Therefore, our equation will look like this:

cos(28)=\frac{32}{x}

Solving for x we have

x=\frac{32}{cos(28)}

Perform that operation on your calculator in degree mode and you'll get that the length of the hypotenuse is 36.2.  If for some reason, your math gave you the length of the hypotenuse and it was shorter than one of the other sides, you did something wrong.  The hypotenuse will ALWAYS be the longest side in a right triangle.

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Nimfa-mama [501]
The answer is 7.50 ......
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4 years ago
Does anyone know this? I’m really stuck
S_A_V [24]

<em>p = 21</em>

Step-by-step explanation:

When you have a midsegment, the base is going to be two times as large as the midsegment. You can find the midsegment if you multiply it by two and set it equal to the base. I have attached a photo below that may help you.

This is the equation we will be using.

2(p-13)=p-5

Now let's solve! Let's start by distributing the 2 by what's in the parentheses.

2p-26=p-5

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7 0
3 years ago
Read 2 more answers
What is the value of cos(150°)?
baherus [9]

ANSWER

-\frac{\sqrt[]{3}}{2}

EXPLANATION

Given

\begin{gathered} \cos \text{ 150} \\  \end{gathered}

We can find cos 150 by using

\begin{gathered} \cos (180-\theta)=-\cos \theta \\ \Rightarrow\cos (180-\theta) \\ =-\cos 30 \end{gathered}

recall that

\begin{gathered} \cos 30=\frac{\sqrt[]{3}}{2} \\  \end{gathered}

Hence,

\begin{gathered} \cos 150=-\cos 30 \\ =-\frac{\sqrt[]{3}}{2} \\  \end{gathered}

Therefore, the value of cos 150 is

-\frac{\sqrt[]{3}}{2}

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1 year ago
Help- I'll give brainliest&lt;3
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Example : number one is 3/20.   LEARN  

Step-by-step explanation:

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3 years ago
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goldenfox [79]

for a triangular prism, its volume will simply be <u>area of its base</u> times its length.

the are of the base for this one is simply any of those triangular bases.  Now, let's notice, the right-triangle has a base of 9 and a height o 9, notice the tickmarks, whilst the prism also has a length of 13.

\bf \stackrel{\textit{area of the triangle}}{\cfrac{1}{2}(9)(9)}~~\cdot~~ \stackrel{\textit{length}}{(13)}\implies 9\cdot 13\implies 117

5 0
3 years ago
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