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Helga [31]
3 years ago
6

The length of a rectangle is 4 inches more than its width. If the area of the rectangle is 45 sq. inches, what is the width?

Mathematics
2 answers:
Softa [21]3 years ago
7 0
L = length
w = width

l = w + 4
A = l * w

45 = (w+4) * w
45 = w^2 + 4w
0 = w^2 + 4w - 45

Use the factors of 45 to identify the missing coefficients.
45: 1, 45, 3, 15, 5, 9 (5 and 9 can give me 45 as the product and 4 as a difference.

(w + 9)(w - 5)

Thus if the length is 4 inches more than its width, the length = 9 inches and the width = 5 inches.
SVEN [57.7K]3 years ago
7 0
The width is 9 bc 5+4 is 9 and 9x5 is45
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Help ASAP will give brainilist
Elenna [48]
It would be: 4 / 2/5

We can re-write it as:

4 * 5/2

= 20/2

= 10

In short, Your Answer would be: 10

Hope this helps!
5 0
4 years ago
Read 2 more answers
You borrow $5,000 from your parents to purchase a used car. The arrangements of the loan are such that you make payments of $250
AfilCa [17]
Part A:
1st month: Interest payable = 1% of $5,000 = $50.00
Amount paid in first month = $250 + $50.00 = $300
Unpaid balance = $5,000 - $250 = $4,750

2nd month: Interest payable = 1% of $4,750 = $47.50
Amount paid in second month = $250 + $47.50 = $297.50
Unpaid balance = $4,750 - $250 = $4,500

3rd month: Interest payable = 1% of $4,500 = $45.00
Amount paid in third month = $250 + $45.00 = $295.00
Unpaid balance = $4,500 - $250 = $4,250

4th month: Interest payable = 1% of $4,250 = $42.50
Amount paid in fouth month = $250 + $42.50 = $292.50
Unpaid balance = $4,250 - $250 = $4,000

5th month: Interest payable = 1% of $4,000 = $40.00
Amount paid in fifth month = $250 + $40.00 = $290.00
Unpaid balance = $4,000 - $250 = $3,750

6th month: Interest payable = 1% of $3,750 = $37.50
Amount paid in sixth month = $250 + $37.50 = $287.50
Unpaid balance = $3,750 - $250 = $3,500

7th month: Interest payable = 1% of $3,500 = $35.00
Amount paid in seventh month = $250 + $35.00 = $285.00
Unpaid balance = $3,500 - $250 = $3,250

8th month: Interest payable = 1% of $3,250 = $32.50
Amount paid in eighth month = $250 + $32.50 = $282.50
Unpaid balance = $3,250 - $250 = $3,000

9th month: Interest payable = 1% of $3,000 = $30.00
Amount paid in ninth month = $250 + $30.00 = $280.00
Unpaid balance = $3,000 - $250 = $2,750

10th month: Interest payable = 1% of $2,750 = $27.50
Amount paid in fouth month = $250 + $27.50 = $277.50
Unpaid balance = $2,750 - $250 = $2,500

11th month: Interest payable = 1% of $2,500 = $25.00
Amount paid in seventh month = $250 + $25.00 = $275.00
Unpaid balance = $2,500 - $250 = $2,250

12th month: Interest payable = 1% of $2,250 = $22.50
Amount paid in eighth month = $250 + $22.50 = $272.50
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Part B:
Number of payments = 5000 / 250 = 20
Total amount of interest = 50 + 47.5 + 45 + . . . + upto the 20th payment.
This is an arithmetic sequence with the first term as 50, common difference as -2.5 and number of terms = 20.

Sum of the first 20th term of the GP is given by
S_n= \frac{20}{2}[2(50)+(20-1)(-2.5)] \\  \\ =10(100-2.5(19))=10(100-47.5) \\  \\ =10(52.5)=\$525.00

Therefore, the <span>total amount of interest paid over the term of the loan is $525.00</span>
8 0
3 years ago
The graph of the cube root parent function y =3^sqrt x
umka2103 [35]

Answer:

f(x) =  \sqrt[3]{x + 6} + 1

Step-by-step explanation:

Whenever addition or subtraction occurs within the cube root, it moves horizontally; the opposite is done for the translation, thus if it is addition, which in this case it is, instead of moving the positive direction, the function moves the negative direction.

As opposed to addition or subtraction outside of the cube root, it moves vertically, and in this case, it is translated exactly as stated. Here it states addition, thus the graph moves up in one unit.

The origin of the parent function is at ( 0, 0), in contrast, the origin of the function is at ( -6, 1 )

By using what we know, we can determine that the answer will be f(x) =  \sqrt[3]{x + 6} + 1 since we know that the inside of the cube root should be the opposite of the x value and the outside of the cube root should be the same.

7 0
3 years ago
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Ksenya-84 [330]
Assuming LCD means Lowest Common Denominator
Assuming by "and" you mean adding the two

Well, you go by the multiples of 7;
7, 14, 21, 28, 35, 42, 49, 56, 63,<u> 70</u>
Multiples of 10;
10, 20, 30, 40, 50, 60, <u>70</u>, 80, 90, 100

Straight away you can see the lowest common multiple is 70,

Now to go about adding them,
2/7 * 10 (both sides) , 20/70
9/10 * 7 (both sides) , 63/70

Then you add the two; 20/70 + 63/70  - now we can add them because they share the same denominator
20/70 + 63/70 = 83/70 = 1 whole 13/70 (simplified)

<u>The LCD is 70

Quick tip, </u>to find a common multiple (not necessarily the lowest) multiply the two denominators. 
8 0
3 years ago
Read 2 more answers
Choose the option with the proper number of sig figs
marishachu [46]
\text{ 2 }\times10^8

Explanation:\begin{gathered} \text{Given:} \\ \frac{9\text{ }\times10^9}{4.5\text{ }\times10^1} \end{gathered}

let's break down the expression to get the final result:

\begin{gathered} \frac{9\text{ }\times10^9}{4.5\text{ }\times10^1}\text{ = }\frac{9}{4.5}\times\text{ }\frac{10^9}{10^1} \\ \frac{9}{4.5}\text{ = }\frac{9\text{ }\times\text{ 10}}{4.5\text{ }\times\text{ 10}}\text{ = }\frac{90}{45} \\ \frac{9}{4.5}\text{ = }2 \\  \\ \frac{10^9}{10^1}\colon\text{ when we divide exponents with same base, } \\ we\text{ take one of the base and combine the exponents by subtracting them:} \\ \frac{10^9}{10^1}=10^{9-1} \\ \frac{10^9}{10^1}=10^8 \end{gathered}\begin{gathered} \frac{9}{4.5}\times\text{ }\frac{10^9}{10^1}\text{ = 2 }\times10^8 \\  \\ \text{when dividing decimals, }the\text{ least number of }significant\text{ }figures\text{ in the problem}, \\ \text{ }\det ermines\text{ the significant figures in the answer} \\ 9\text{ = 1 significant, 4.5 = 2 significant} \\ \text{The least significant is 1} \\  \\ \frac{9\text{ }\times10^9}{4.5\text{ }\times10^1}\text{ = 2 }\times10^8 \end{gathered}

6 0
1 year ago
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