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vovangra [49]
3 years ago
15

What is the answer to this question

Mathematics
1 answer:
il63 [147K]3 years ago
6 0
The ratio of the shortest sides is 12/5. Multiplying the other two sides of the smaller triangle by that ratio gives 15 and 18, so the ratios of all sides are the same. The triangles are similar.

ABC ~ ZYX

The largest/smallest scale factor is 12/5 = 2.4.
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70%70, percent of a number is what fraction of that number?
lesantik [10]

Hello there!

A number that is 70% of a number is 7/10 of that number in fraction form!

I hope this was helpful and have a great rest of your day!

3 0
4 years ago
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Which of the following shapes describes the 2d figure formed by slicing parallel to the base of a triangular prism
Arte-miy333 [17]

Answer:

c. square.

Step-by-step explanation:

squares have 4 parallel sides so if you cut it in half you will still be parallel

7 0
3 years ago
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How much water do you need to add to make each concentration?<br> 1% sugar syrup using 12 g sugar
yulyashka [42]

Answer:

1188 grams of water

Step-by-step explanation:

x is the grams of water

so total is 12+x grams

sugar/total is 12/12+x

and 1% ratio is 12/12+x=1/100

so x would be 1188 grams of water.

6 0
3 years ago
Please answer asap.........
iren [92.7K]

Answer:

1.4 i would wait for someone else to answer it I'm not sure

Step-by-step explanation:

5 0
3 years ago
Toxaphene is an insecticide that has been identified as a pollutant in the Great Lakes ecosystem. To investigate the effect of t
Likurg_2 [28]

Answer:

This data suggest that there is more variability in low-dose weight gains than in control weight gains.

Step-by-step explanation:

Let \sigma_{1}^{2} be the variance for the population of weight gains for rats given a low dose, and \sigma_{2}^{2} the variance for the population of weight gains for control rats whose diet did not include the insecticide.

We want to test H_{0}: \sigma_{1}^{2} = \sigma_{2}^{2} vs H_{1}: \sigma_{1}^{2} > \sigma_{2}^{2}. We have that the sample standard deviation for n_{2} = 22 female control rats was s_{2} = 28 g and for n_{1} = 18 female low-dose rats was s_{1} = 51 g. So, we have observed the value

F = \frac{s_{1}^{2}}{s_{2}^{2}} = \frac{(51)^{2}}{(28)^{2}} = 3.3176 which comes from a F distribution with n_{1} - 1 = 18 - 1 = 17 degrees of freedom (numerator) and n_{2} - 1 = 22 - 1 = 21 degrees of freedom (denominator).

As we want carry out a test of hypothesis at the significance level of 0.05, we should find the 95th quantile of the F distribution with 17 and 21 degrees of freedom, this value is 2.1389. The rejection region is given by {F > 2.1389}, because the observed value is 3.3176 > 2.1389, we reject the null hypothesis. So, this data suggest that there is more variability in low-dose weight gains than in control weight gains.

8 0
3 years ago
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