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Flura [38]
3 years ago
5

20n^4+n^3+10n^2) / 10n^2

Mathematics
1 answer:
Zina [86]3 years ago
3 0
Divide them
We'd get
2n^2+1/10n + 1
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A rectangle has a perimeter of 84 meters and a length of 35 meters. What is the width of the rectangle?
BaLLatris [955]
To find the perimeter of a rectangle, we can use this formula: 2L + 2W
Where L is the length and W is the width.

We know the perimeter and we know the length and we want to find the width.
Substitute the values back into the formula.

2(35) + 2W = 84
70 + 2W = 84
2W = 14 <-- Subtract both sides by 70
W = 7 <-- Divide both sides by 2

So, width is 7 meters long.

8 0
3 years ago
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A bag contains 20 marbles of the same size that are blue, green, and red. The probability of picking a blue marble is 20%. The p
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The probability of picking up a red marble is 30%
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3 years ago
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Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)
Mnenie [13.5K]
One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
(x-h)^2+(y-k)^2=r^2
the center is (h,k) and the radius is r

and the distance formula is
distance between (x_1,y_1) and (x_2,y_2) is
D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}


r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle


so
(x+2)^2+(y-3)^2=18
(x-(-2))^2+(y-3)^2=(\sqrt{18})^2
(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2

the radius is 3\sqrt{2}
center is (-2,3)

find distance between (8,4) and (-2,3)

D=\sqrt{(8-(-2))^2+(4-3)^2}
D=\sqrt{(8+2)^2+(1)^2}
D=\sqrt{10^2+1}
D=\sqrt{100+1}
D=\sqrt{101}




r=3\sqrt{2}≈4.2
D=\sqrt{101}≈10.04

do r<D

(8,4) is outside the circle

6 0
3 years ago
Marking brainliest...
anastassius [24]

Answer:

D

Step-by-step explanation:

7 0
2 years ago
Three segments of lengths 25 cm, 37 cm, and 62 cm will form a triangle.
Llana [10]
Ok....
What am I supposed to answer here???
6 0
3 years ago
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