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Murrr4er [49]
3 years ago
13

Need some help with this math question, can someone help me out pls

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
3 0

Okay I'm not too sure on this but I believe it is the third one.

I hope this helps!!

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are yall just using this thing to cheat on your tests LOL i swear im seeing so many people asking questions that look like theyr
Oliga [24]

Answer:

that's what most people use it for I believe

5 0
3 years ago
Help, this is confusing for me
garri49 [273]

Answer:

B: 163,343

Step-by-step explanation:

V=πr²h 34²=1156, 1156×45=52020, 52020×3.14(π)=163,342.8, then round up.

4 0
3 years ago
Determine the total number of roots of each polynomial function using the factored form. f (x) = (x + 5)3(x - 9)(x + 1)
densk [106]

Answer:

Answer is 5

Step-by-step explanation:

Okay hun so let me tell u what's up here

They give us this equation and ask for the 'roots'

(x+5)^3(x-9)(x+1)

Now lemme tell you the roots of this one

-5, 9, -1

you get this from making each of them 0

The answer to this would be "3" because there are 3 roots, buT wait theRe'S mOre

(x+5) goes 3 times

So thy must recount it

-5, -5, -5, 9, -1 <-- These are the roots

that's 5 roots in total

....also I did this on edgen, got it right with 5

5 0
3 years ago
Read 2 more answers
12 – 7x ≤-2 <br> solve and show work
vova2212 [387]

Answer:

x≥2

Step-by-step explanation:

Let's solve your inequality step-by-step.

12−7x≤−2

Step 1: Simplify both sides of the inequality.

−7x+12≤−2

Step 2: Subtract 12 from both sides.

−7x+12−12≤−2−12

−7x≤−14

Step 3: Divide both sides by -7.

−7x/−7 ≤ −14/−7

x≥2

8 0
2 years ago
A researcher determines that students are active about 60 + 12 (M + SD) minutes per day. Assuming these data are normally distri
rjkz [21]

Answer:

The correct option is (b).

Step-by-step explanation:

If X \sim N (µ, σ²), then Z=\frac{X-\mu}{\sigma}, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z \sim N (0, 1).

The distribution of these z-variate is known as the standard normal distribution.

The mean and standard deviation of the active minutes of students is:

<em>μ</em> = 60 minutes

<em>σ </em> = 12 minutes

Compute the <em>z</em>-score for the student being active 48 minutes as follows:

Z=\frac{X-\mu}{\sigma}=\frac{48-60}{12}=\frac{-12}{12}=-1.0

Thus, the <em>z</em>-score for the student being active 48 minutes is -1.0.

The correct option is (b).

4 0
3 years ago
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