Hello, It is very simples.
Look it :
Let a^3 - b^3 = ?
Add on both th side -3a^2b + 3ab^2
a^3 -3a^2b + 3ab^2 -b^3 = ?
-3a^2b+3ab^2
The firs equation is = (a - b)^3
Then,
(a - b)^3 = ? + 3a^2b - 3ab^2
Passing -3a^2b + 3ab^2 to the left side:
But changing the sinal
? = (a - b)^3 + 3a^2b - 3ab^2
? = (a - b)^3 + 3ab ( a - b)
Putting (a - b) as commun factor
? = (a - b).[ 3ab + (a - b)^2 ]
As (a - b)^2 = a^2 - 2ab + b^2
Then,
? = (a - b).[ 3ab + a^2 -2ab +b^2]
? = (a - b).( a^2 + ab + b^2)
I hope helps!
Answer:
y = 1/5x + 2 1/5
Step-by-step explanation:
first find the negative reciprocal slope of 5x + y = 30 because perpendicular lines have negative reciprocal slope:
=> y = -5x + 30, negative reciprocal of the slope -5 is 1/5
substitute the new slope 1/5 and the coordinate (9, 4) into the equation: y = mx + b to solve for b
=> 4 = 1/5(9) + b
=> 4 = 9/5 + b
=> b = 2 1/5
plug in the slope 1/5 and b = 2 1/5 into the equation: y = mx + b
=> y = 1/5x + 2 1/5
Answer:
The point (1 | 6) is on the graph.
Step-by-step explanation:
Answer:21
Step-by-step explanation:becausebecausebecau se i know
