Ask question

Ask question

All categories

3 years ago

5

Use proportions to solve the following problem. A recipe calls for 4 eggs and 3 cups of milk. To prepare for a larger number of

guests, a cook uses 22 eggs. How many cups of milk are needed?

1 answer:

dybincka [34]3 years ago

3 0

Answer:

16.5 cups of milk are needed.

Step-by-step explanation:

i hate you for reporting my answer.

You might be interested in

What is the answer to N2+n-30

Liono4ka [1.6K]

I got two solutions <span> n = 6<span> and n = -5</span></span>

5 0

4 years ago

Suppose that S'T'U is the result of a dilation STU with center T and scale factor 2. What are the coordinates of point S'?

7nadin3 [17]

Given that STU is dilated by a scale factor of 2, the resulting rule is (x, y) ⇒ (2x, 2y)

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Dilation is the increase or decrease in the size of a figure by a scale factor.

Given that STU is dilated by a scale factor of 2, the resulting rule is (x, y) ⇒ (2x, 2y)

Find out more on equation at: brainly.com/question/2972832

#SPJ1

4 0

2 years ago

What is a true statement

leva [86]

Answer:

Noun. 1. true statement - a true statement; "he told the truth"; "he thought of answering with the truth but he knew they wouldn't believe it" truth.

4 0

4 years ago

A tank contains 250 liters of fluid in which 40 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu

VashaNatasha [74]

Answer:

$A(t)=250-210e^{-\frac{t}{50}}$

Step-by-step explanation:

We are given that

Volume,V=250 L

Mass of salt=m=40 g

Brine containing 1 g per liter

Pumped into the tank at the rate=5 L/min

We have to find the number A(t) of grams of salt in the tank at time t.

Rate of change of salt in the tank

$\frac{dA}{dt}=$ Rate in-Rate out

Rate in=5 L/min

Rate out= $\frac{A}{250}\times 5=\frac{A}{50}$ L/min

$\frac{dA}{dt}=5-\frac{A}{50}=\frac{250-A}{50}$

$\int \frac{50dA}{250-A}=\int dt$

$-50ln(250-A)=t+C$

Using the formula

$\int \frac{dx}{x}=ln x$

A=40 and t=0

$-50ln(250-40)=0+C$

$-50ln(210)=C$

Substitute the value

$-50ln(250-A)=t-50ln(210)$

$-50ln(250-A)+50ln(210)=t$

$50ln\frac{210}{250-A}=t$

$t=50ln\frac{210}{250-A}$

$\frac{t}{50}=ln\frac{210}{250-A}$

$\frac{210}{250-A}=e^{\frac{t}{50}$

$\frac{250-A}{210}=e^{-\frac{t}{50}}$

$250-A=210e^{-\frac{t}{50}}$

$A(t)=250-210e^{-\frac{t}{50}}$

8 0

4 years ago

2. At Burger World, you can buy a party platter of 25 burgers for $75. What

Montano1993 [528]

$3 per burger. You divide 75 by 25.

4 0

3 years ago