Find the equation of the Circle P.

Which exponential equation is equivalent to the logarithmic equation below? log 478= a

marta [7]

$\hbox{if } \log_x y=z \hbox{ then } x^z=y \\ \\
\log 478=a \\ \downarrow \\
\log_{10} 478=a \\ \Downarrow \\ \boxed{10^a=478}$

The answer is A.

5 0

3 years ago

A cube has a volume of 64 m3<br> What are its height, width and length?

Monica [59]

The answer above is correct

3 0

3 years ago

Work out: x+3 5x-2 and x=8 <br> A)><br> B)<<br> C)=

Ilia_Sergeevich [38]

The correct answer is < (B)
8+3 is 11
5*8 is 40 then take 2 away and you will get 38
11<38

3 0

3 years ago

A cone is inverted and filled with water to of its height. What percent of the cone's volume is filled with water

wlad13 [49]

The 75% of the cone's volume is filled with water.

According to the statement

we have to find that the What percent of the cone's volume is filled with water.

So, For this purpose, we know that the

Cone is the surface traced by a moving straight line that always passes through a fixed point (the vertex).

So, Form given information

Let's call the height of the cone " h " and the area of its base " a ".

volume of cone = (1/3)(a)(h)

The water will also be in the shape of a cone, with a height that is 3/4 that of the container.

volume of water = (1/3)(a)(3/4 * h)

volume of water = (3/4) * (1/3)(a)(h)

volume of water = (3/4) * volume of cone

volume of water = 75% of the volume of cone

So, 75% of the cone's volume is filled with water.

Learn more about cone's volume here

brainly.com/question/1082469

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Question:

A cone is inverted and filled with water to 3/4 of its height. What percent of the cone's volume is filled with water?

#SPJ4

8 0

1 year ago

I am extremely confused, can anyone help?

JulijaS [17]

Answer:

So I did most of you table for you:

First blank:4

Second blank:-4

Third blank:-8

Fourth blank: Left to you: Just plug in 6 into 1/2x^2-5x+4 (I will check)

Fifth blank: Left to you: Just plug in 8 into 1/2x^2-5x+4 (I will check)

The graph is D.

Step-by-step explanation:

So they have a table to fill in and they tell you in the first row what they want you to plug in

So the table is asking us to answer this:

What is h(0),h(2),h(4),h(6), and h(8).

h(0) means to replace x with 0 in $\frac{1}{2} x^2-5x+4$ .

$\frac{1}{2}(0)^2-5(0)+4$

$0-0+4$

$0+4$

$4$

So the first blank is 4 since h(0)=4.

h(2) means to replace x with 2 in $\frac{1}{2} x^2-5x+4$ .

$\frac{1}{2} (2)^2-5(2)+4$

$\frac{1}{2} (4)-10+4$

$2-10+4$

$-8+4$

$-4$

So the second blank is -4 since h(2)=-4.

h(4) means to replace x with 4 in $\frac{1}{2} x^2-5x+4$ .

$\frac{1}{2}(4)^2-5(4)+4$

$\frac{1}{2}(16)-20+4$

$8-20+4$

$-12+4$

$-8$

So the third blank is -8 since h(4)=-8

Maybe you can try the last 2 blanks in the table part. That is try computing h(6) and h(8). I will check it for you.

Now the points I have so far are (0,4) from the h(0)=4, (2,-4) from the h(2)=-4, and (4,-8) from the h(4)=-8.

I'm looking for a graph that goes through these points (0,4) , (2,-4) , and (4,-8).

By the way the only graphs that are worth looking at is C and D because they are open up. I know my curve for h(x)=1/2x^2-5x+4 should be a parabola open up because 1/2 is positive and 1/2 is the coefficient of x^2.

So Graph C has y-intercept (0,10) not (0,4) so Graph C is not right.

Graph D has y-intercept (0,4). It also goes through (2,-4) and (4,-8).

I don't know if you notice but the x-axis and y-axis are going up by two's in each graph.

7 0

3 years ago