Select the correct answer.

The table shows Ava's checking account activity for several weeks. Ava's beginning balance was $685. What was her ending balance

Dafna11 [192]

B. Deposit means she added money to her account so you would add 175 and 180 to 685 (giving you 1040). Withdrawal means she took money out of her account so you would subtract 240, 140, and 350 from 1040 giving you your answer of $310 :)

8 0

3 years ago

Tyler needs to get the windows in his new home cleaned. The cleaning company needs to know the total number of window panes befo

ANTONII [103]

Answer:

I believe it's (4^2)*12

Step-by-step explanation:

To find the correct amount of the window panes there are, we have to find how much window pains are in each of the window's. So we have a 4 by 4 so that's 16. Then we have to do 16*12 to get the total amount of panes since Panes Per Window multiplied by Number Of Windows equals Total Number Of Panes

Hope this helps! ∪ω∪

3 0

3 years ago

Read 2 more answers

The diameter of a wheel of a car is 30cm. If the car travels at an average speed of 13.2m/s, find the number of revolutions made

Marysya12 [62]

Answer:

Approximately $50420$ revolutions (rounded to the nearest whole number.)

Step-by-step explanation:

Convert the diameter of this wheel to meters: $d = 30\; \rm cm = 0.30\; \rm m$ .

Circumference of this wheel:

$\pi \, d = \pi \times 0.30\; \rm m \approx 0.942\; \rm m$ .

Distance travelled in one hour:

$\begin{aligned}v \cdot t &= 13.2 \; \rm m \cdot s^{-1} \times 3600\; \rm s \\ &= 47520\; \rm m\end{aligned}$ .

Number of revolutions required for covering that distance:

$\displaystyle \frac{47520\; \rm m}{(\pi \times 0.30\; \rm m)} \approx 50420$ .

3 0

3 years ago

Consider an experiment where two 6-sided dice are rolled. We can describe the ordered sample space as below where the first coor

agasfer [191]

Answer:

$E$ = { (4,1) , (3,2) , (2,3) , (1,4) }

$P(E)=\frac{1}{9}$

$P(F|E)=\frac{1}{4}$

Step-by-step explanation:

Let's start writing the sample space for this experiment :

$S=$ { (1,1) , (1,2) , (1,3) , (1,4) , (1,5) , (1,6) , (2,1) , (2,2) , (2,3) , (2,4) , (2,5) , (2,6) , (3,1) , (3,2) , (3,3) , (3,4) , (3,5) , (3,6) , (4,1) , (4,2) , (4,3) , (4,4) , (4,5) , (4,6) , (5,1) , (5,2) , (5,3) , (5,4) , (5,5) , (5,6) , (6,1) , (6,2) , (6,3) , (6,4) , (6,5) , (6,6) }

Let's also define the event $E$ ⇒

$E$ : '' The sum of the two dice is 5 ''

We can describe the event by listing all the favorables cases from $S$ ⇒

$E$ = { (4,1) , (3,2) , (2,3) , (1,4) }

In order to calculate $P(E)$ we are going to divide all the cases favorables to $E$ over the total cases from $S$ . We can do this because all 36 of these possible outcomes from $S$ are equally likely. ⇒