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JulsSmile [24]
3 years ago
6

HCFof 506 and 1863

Mathematics
1 answer:
Bogdan [553]3 years ago
4 0

Answer:

The hcf of 506 and 1863 is 23

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Simplify: (sin θ − cos θ)^2 − (sin θ + cos θ)^2 A) −4sin(θ)cos(θ) B) 2 C) sin^2 θ D) cos^2 θ
N76 [4]

Answer:

-4sinθcosθ

Step-by-step explanation:

Note:

1. (a + b)^2 = a^2 + 2ab + b^2

2. (a - b)^2 = a^2 - 2ab + b^2

3. sin^2θ + cos^2θ = 1

(sinθ -cosθ)^2 - (sinθ + cosθ)^2

= sin^2θ - 2sinθcosθ + cos^2θ - (sin^2θ + 2sinθcosθ + cos^2θ)

= sin^2θ + cos^2θ - 2sinθcosθ - (sin^2θ + cos^2θ + 2sinθcosθ)

= 1 - 2sinθcosθ - (1 + 2sinθcosθ)

= 1- 2sinθcosθ -1 - 2sinθcosθ

= - 2sinθcosθ - 2sinθcosθ

= -4sinθcosθ

3 0
3 years ago
What is the sale price 45% of 69.50
Zolol [24]
   x         55
-------- = ---------
69.50     100

69.50*55= 3822.5
3822.5/100= 38.225
x=$38.22
5 0
3 years ago
a regular hexagonal nut of side 1 cm and length 3 cm with a central hole of diameter 1 cm. 3 cm 1 cm 1 cm. Calculate the volume
Bogdan [553]

Answer:

  5.44 cm³

Step-by-step explanation:

The volume of the hexagonal nut can be found by multiplying the area of the end face by the length of the nut. The end face area is the difference between the area of the hexagon and the area of the hole.

The area of a hexagon with side length s is given by ...

  A = (3/2)√3·s²

For s=1 cm, the area is ...

  A = (3/2)√3(1 cm)² = (3/2)√3 cm²

__

The area of a circle is given by ...

  A = πr²

The radius of a circle with diameter 1 cm is 0.5 cm. Then the area of the hole is ...

  A = π(0.5 cm)² = 0.25π cm²

__

The volume is the face area multiplied by the length, so is ...

  V = Bh = ((3/2)√3 -0.25π)(3) . . . . . cm³

  V = (9/2)√3 -0.75π cm³ ≈ 5.44 cm³

The volume of the metal is about 5.44 cm³.

5 0
3 years ago
1+4.25n+3/2p-3+(-2p)+5/4n
alex41 [277]

Answer:

11/2n+-1/2p-2

Step-by-step explanation:

simplification

3 0
3 years ago
Gertrude Treemason pays 11% annual interest on her Visa card. She has a balance of $2,200. What is the effective annual interest
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The annual interest is $242
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