divisions between $389$ and $390$ so each division is $\frac{390-389}{10}=0.1$
A is 8 division from $389$, so, A is $389+8\times 0.1=389.8$
similarly, C is one division behind $389$ so it is $389-1\times 0.1=388.9$
and B is $390.3$
It is 12495 for sure i took the test and got it right
Answer:
y = –7x – 11
6x – 4y = 10
Step-by-step explanation:
From the question given above, we obtained:
x = –1
y = –4
y = ?x – 11 ....... (1)
6x – ?y = 10b......... (2)
Let the two unknown be a and b. Thus the above equation becomes:
y = ax – 11 ......... (3)
6x – by = 10 .......(4)
Next, we shall determine the value of 'a' and 'b'. This can be obtained as follow:
For a:
y = ax – 11
x = –1
y = –4
–4 = a(–1) – 11
–4 = –a – 11
Collect like terms
–4 + 11 = –a
7 = –a
Multiply through by –1
a = –7
For b:
6x – by = 10
x = –1
y = –4
6(–1) – b(–4) = 10
–6 + 4b = 10
Collect like terms
4b = 10 + 6
4b = 16
Divide both side by 4
b = 16 / 4
b = 4
Finally, we shall substitute the value of a and be into equation 3 and 4 respectively.
y = ax – 11
a = –7
y = –7x – 11
6x – by = 10
b = 4
6x – 4y = 10
Therefore, the complete equation are:
y = –7x – 11
6x – 4y = 10
The length of ND = 3 units
The length of N'D' = 6
6 / 3 = 2
The scale factor is 2
Answer:
a. 14
Step-by-step explanation:
make equations
2x this is how old trinity is
x + 2x =42 their ages combined, solve equation
3x =42
14
