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vazorg [7]
3 years ago
15

Which expression is equivalent to the expression (7×2)^7​

Mathematics
1 answer:
ddd [48]3 years ago
7 0

Answer:

9^7

Step-by-step explanation:

7*2=9

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write the equation of the line, in standard form, that passes through the origin and is parallel to x+y=6. include your work in
tankabanditka [31]
To solve this problem you must apply the proccedure shown below:
 You have that the line is <span>parallel to x+y=6, this means that both  lines have the same slope. You can calculate the slope as below:
 y=mx+b
 m is the slope and b is the y-intercept

 x+y=6
 y=-x+6
 The slope is m=-1

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4 0
3 years ago
A principle of $12000 was invested into 2 accounts. One account was invested in muni bonds which generated 6% interest rate. The
Keith_Richards [23]

Answer:

Sorry, I don't know

Step-by-step explanation:

6 0
3 years ago
14 5 18 24 15 28 34 _ what number is needed to complete the pattern
AlekseyPX
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4 0
3 years ago
Which shows one way to determine the factors of x3 11x2 – 3x – 33 by grouping? x2(x 11) 3(x – 11) x2(x – 11) – 3(x – 11) x2(x 11
Aloiza [94]

The one way to determine factors of x³  + 11x² – 3x – 33  will be x^2(x+11)-3(x+11)_.

<h3>What is a factorization?</h3>

It is the method to separate the polynomial into parts and the parts will be in multiplication. And the value of the polynomial at this point will be zero.

The steps involved in the factorization are;

1. For each pair of parentheses, we create a common factor.

2. We use x2 as a common factor for the first parenthesis.

3. We use common factor 3 for the second parenthesis.

x^3  + 11x^2 - 3x -33 \\\\ x^2(x+11)-3(x+11)_

We will find the final solution as x^2(x+11)-3(x+11)_.

Hence the one way to determine factors of x³  + 11x² – 3x – 33  will be x^2(x+11)-3(x+11)_.

To learn more about the factorization refer to the link;

brainly.com/question/24182713

3 0
2 years ago
297 words in 5.5 minutes ? im confused again
Vedmedyk [2.9K]

Answer:

The unit rate of 297 words for 5.5 minutes is, 54 words per minutes

hope this helps :-)

5 0
2 years ago
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