For a function to begin to qualify as differentiable, it would need to be continuous, and to that end you would require that 
is such that
Obviously, both limits are 0, so 
is indeed continuous at 
.
Now, for to be differentiable everywhere, its derivative 
must be continuous over its domain. So take the derivative, noting that we can't really say anything about the endpoints of the given intervals:
and at this time, we don't know what's going on at , so we omit that case. We want to be continuous, so we require that
from which it follows that 
.
Step-by-step explanation:
step 1. I guess we assumed the two lines across the transversal are parallel
step 2. 3x + 1 = 85 (definition of alternate exterior angles)
step 3. 3x = 84 (subtract 1 from each side)
step 4. x = 28. (divide both sides by 3)
Answer:
50.24 (unit squared! cm2, m2, etc.)
Step-by-step explanation:
Area is: Pi x r^2
3.14 x 4^2 = 3.14 x 16 = 50.24
Answer:
41
Step-by-step explanation:
an = a1 + (n-1)d
a_n = the nᵗʰ term in the sequence = 10
a_1 = the first term in the sequence = 5
d = the common difference between terms = 4
a10 = 5 + (10-1)4
a10 = 5 + (9)4
a10 = 5 + 36
a10 = 41
