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kirill [66]
3 years ago
5

Make 'r' the subject of the formula: v = 4

alt=" \pi " align="absmiddle" class="latex-formula">r²h

(Thanks!)
Mathematics
2 answers:
Vika [28.1K]3 years ago
5 0

v = 4π r²h is to be solved for r.


Divide both sides of this equation by 4π*h:


     v

--------- = r^2

   4π*h


Next, take the positive square root of both sides:


              v

r = √[----------- ]

           4π*h


You may leave this result as is, or proceed further:  Taking the + square root of 4 results in:

                      v

r = (1/2)√[----------- ]

                    π*h


earnstyle [38]3 years ago
5 0

V=4\pi r^2h\\\\ r^2=\dfrac{V}{4\pi h }\\\\ r=\sqrt{\dfrac{V}{4\pi h }}\\\\ r=\dfrac{\sqrt V}{\sqrt{4\pi h} }\\\\ r=\dfrac{\sqrt V}{2\sqrt{\pi h} }\\\\ r=\dfrac{\sqrt {\pi h V}}{2}\\\\

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Answer:

C

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6 0
3 years ago
-4/5 to the power of 2 times -3/50
Crazy boy [7]
=(-4/5)^2 * -3/50
square -4/5 first; remember -4/5^2 is the same as -4/5 * -4/5

=(-4/5 * -4/5) * -3/50
multiply -4 numerators; multiply 5 denominators

=(-4 * -4)/(5 * 5) * -3/50

=16/25 * -3/50
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= -48/1250

simplify by 2
= -24/625 (or -0.0384)


ANSWER: -24/625 (or -0.0384)

Hope this helps! :)
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