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kirill [66]
3 years ago
5

Make 'r' the subject of the formula: v = 4

alt=" \pi " align="absmiddle" class="latex-formula">r²h

(Thanks!)
Mathematics
2 answers:
Vika [28.1K]3 years ago
5 0

v = 4π r²h is to be solved for r.


Divide both sides of this equation by 4π*h:


     v

--------- = r^2

   4π*h


Next, take the positive square root of both sides:


              v

r = √[----------- ]

           4π*h


You may leave this result as is, or proceed further:  Taking the + square root of 4 results in:

                      v

r = (1/2)√[----------- ]

                    π*h


earnstyle [38]3 years ago
5 0

V=4\pi r^2h\\\\ r^2=\dfrac{V}{4\pi h }\\\\ r=\sqrt{\dfrac{V}{4\pi h }}\\\\ r=\dfrac{\sqrt V}{\sqrt{4\pi h} }\\\\ r=\dfrac{\sqrt V}{2\sqrt{\pi h} }\\\\ r=\dfrac{\sqrt {\pi h V}}{2}\\\\

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The number of terms in the given arithmetic sequence is n = 10. Using the given first, last term, and the common difference of the arithmetic sequence, the required value is calculated.

<h3>What is the nth term of an arithmetic sequence?</h3>

The general form of the nth term of an arithmetic sequence is

an = a1 + (n - 1)d

Where,

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<h3>Calculation:</h3>

The given sequence is an arithmetic sequence.

First term a1 = 1\frac{1}{2} = 3/2

Last term an = 2\frac{1}{2} = 5/2

Common difference d = 1/9

From the general formula,

an = a1 + (n - 1)d

On substituting,

5/2 = 3/2 + (n - 1)1/9

⇒ (n - 1)1/9 = 5/2 - 3/2

⇒ (n - 1)1/9 = 1

⇒ n - 1 = 9

⇒ n = 9 + 1

∴ n = 10

Thus, there are 10 terms in the given arithmetic sequence.

learn more about the arithmetic sequence here:

brainly.com/question/503167

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Disclaimer: The given question in the portal is incorrect. Here is the correct question.

Question: If the first and the last term of an arithmetic progression with a common difference are 1\frac{1}{2}, 2\frac{1}{2} and 1/9 respectively, how many terms has the sequence?

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