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kirill [66]
3 years ago
5

Make 'r' the subject of the formula: v = 4

alt=" \pi " align="absmiddle" class="latex-formula">r²h

(Thanks!)
Mathematics
2 answers:
Vika [28.1K]3 years ago
5 0

v = 4π r²h is to be solved for r.


Divide both sides of this equation by 4π*h:


     v

--------- = r^2

   4π*h


Next, take the positive square root of both sides:


              v

r = √[----------- ]

           4π*h


You may leave this result as is, or proceed further:  Taking the + square root of 4 results in:

                      v

r = (1/2)√[----------- ]

                    π*h


earnstyle [38]3 years ago
5 0

V=4\pi r^2h\\\\ r^2=\dfrac{V}{4\pi h }\\\\ r=\sqrt{\dfrac{V}{4\pi h }}\\\\ r=\dfrac{\sqrt V}{\sqrt{4\pi h} }\\\\ r=\dfrac{\sqrt V}{2\sqrt{\pi h} }\\\\ r=\dfrac{\sqrt {\pi h V}}{2}\\\\

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Step-by-step explanation:

For each year we will have to constantly decrease it by 7.5%

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The answer is:  x² – 6x + 9 = 0  .
_____________________________________________________
Explanation:
________________________________________________________

Given:  (x – 3)² = 0 ;  write as: general form:  "ax² + bx + c = 0";  a ≠ 0 .
<span>
Note:  </span>(x – 3)² = (x – 3)(x – 3) = x² – 3x – 3x + 9 = x² – 6x + 9 ;
___________________________________________________
Rewrite: (x – 3)²  =  0 ;  →
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→   x² – 6x + 9 = 0  ; is in "general form", or "standard equation format"; that is: " ax² + bx + c = 0 ";  (a ≠ 0) ;
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   b = -6; 
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