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mezya [45]
3 years ago
10

Please help me i dont get it at all

Mathematics
1 answer:
Hitman42 [59]3 years ago
8 0

y = 218.2. The lenght of side y by  trigonometry is 218.2.

In order to solve this problem we are going to use the angles and sides of a right triangle and its relation by expressions that we call trigonometric ratios.

In the image we can see that the lenght of the opposite leg is 141 , we do not know the lenght of the adjacent leg y and the hypotenuse x. The key to solve this problem is to use trigonometric ratios and the equation tan θ = sin θ/cos θ = opposite leg/adyacent leg = 141/y

Clear for y for the equation tan θ = sin θ/cos θ = 141/y, we obtain:

y = arctan θ (141)

y = arctan (43°)(141) = 218.2

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Allen is horrible at managing his money. For example, he
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Answer:

$80,000

Step-by-step explanation:

<u>Define the variables</u>:

Let x =  "fish-flavored" chicken company investment (in dollars)

Let y = spray-on vitamins company investment (in dollars)

If Allen invested a total of $100,000:

⇒ x + y = 100000

Given:

  • 3% profit on "fish-flavored" chicken investment
  • 1% profit on pray-on vitamins investment
  • Total profit = $2,600

⇒ 0.03x + 0.01y = 2600

Rewrite the first equation to make y the subject:

⇒ y = 100000 - x

Substitute into the second equation and solve for x:

⇒ 0.03x + 0.01(100000 - x) = 2600

⇒ 0.03x + 1000 - 0.01x = 2600

⇒ 0.02x + 1000 = 2600

⇒ 0.02x = 1600

⇒ x = 80000

Therefore, Allen invested $80,000 in the "fish-flavored" chicken company.

6 0
1 year ago
A company has developed a training procedure to improve scores on the SAT. Following the training, 100 high school students take
Pani-rosa [81]

Answer:

The calculated t-test = 1.717 < 1.6604 at 0.05 level of significance

Null hypothesis is accepted at 0.05 level of significance

A company has developed a training procedure is significantly improve scores

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given  sample mean (x⁻ )  = 517

sample standard deviation (s) =90

Mean of the Population (μ) =500

<em>Null Hypothesis :- H₀ :  </em> (μ) =500

Alternative Hypothesis : H₁ :  μ ≠ 500

<u><em>Step(ii)</em></u>:-

Test statistic

                         t = \frac{x^{-} -mean}{\frac{s}{\sqrt{n} } }

                        t = \frac{517 -500}{\frac{90}{\sqrt{100} } }

                        t  =   1.717

<em>Level of significance</em>

                      ∝ = 0.05

                    t₀.₀₅ = 1.6604

The calculated t-test = 1.717 < 1.6604 at 0.05 level of significance

<u><em>Conclusion</em></u>:-

Null hypothesis is accepted at 0.05 level of significance

A company has developed a training procedure is significantly improve scores

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