Given:
m/n-3(m+n)
m=-10 and n=-2
Solving:
-10/-2-3(-10-2) Since m=-10 and n=-2, we substitute them in for the values since they have an equal relationship.
Now, follow Orders of Operations: PEMDAS
-10/-2-3(-12) Simplify parentheses (P)
There are no Exponents (E)
Multiplication (M) and Division (D) are =, so we do whatever operation comes from the left to right.
-10/-2=5 Division comes first on the left.
therefore:
5-3(-12)
-3(12)=-36, Multiplication is last on the right.
therefore:
5-36
5-36=-31 After M/D, we do Addition and Subtraction, which are also =, so we do them left to right.
Therefore -10/-2-3(-10-2)=-31
We will break this down into its parts:
We know that this is a fraction where the numerator is √(-1) = i
The denominator:
4 - 3i - (2 + 5i); we put 2 + 5i in brackets because we are to subtract its quantity.
Simplifying the denominator:
4 - 3i - 2 - 5i
= 2 - 8i
Now, we write the expression in fractional form:
i / (2 - 8i)
To remove an imaginary number from the denominator, we multiply and divide by its conjugate. The conjugate of a + bi is a - bi
i(2 + 8i) / (2² - (8i)²)
= (-8 + 2i) / (4 + 64)
= -2/17 + i/34
Answer:
a+b/a=5/3+b
Step-by-step explanation:
a+b/a-b=5/3
a+b/a=5/3+b
Answer:
Step-by-step explanation:
where is the pic of the problem
