Hello,
The points are:
(2,1); (1,5/3); (5,-1)
Bye:-)
Answer:
Given f(x) and g(x), please find (fog)(X) and (gof)(x) f(x) = 2x g(x) = x+3
Given f(x) and g(x), please find (fog)(X) and (gof)(x)
f(x) = 2x g(x) = x+3
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Quick Answer
(fog)(x) = 2x + 6
(gof)(x) = 2x + 3
Expert Answers
HALA718 eNotes educator| CERTIFIED EDUCATOR
f(x) = 2x
g(x) = x + 3
First let us find (fog)(x)
(fog)(x) = f(g(x)
= f(x+3)
= 2(x+3)
= 2x + 6
==> (fog)(x) = 2x + 6
Now let us find (gof)(x):
(gof)(x) = g(f(x)
= g(2x)
= 2x + 3
==> (gof)(x) = 2x + 3
Step-by-step explanation:
2nd, 4th, and 5th answers are correct
<span>If the sum of two of the sides congruent to each other are greater than that of the sides opposite them, then no. If however the kite forms a rombus ot square, the diagnoles will form four congruent triangles with the base of both being the line of symmetry.
hope this helps :)</span>
Alright, so we'd use the combinations with repetition formula, so we choose from 4 schools to distribute to and distribute 8 blackboards. It's then
( 8+4-1)!/8!(4-1)!=11!/(3!*8!)=165
For at least one blackboard, we first distribute 1 to each school and then have 4 blackboards left, getting (4+4-1)!/4!(4-1)!=7!/(4!*3!)=35
