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2 years ago

Solve by factoring please help this is timed :(

Mathematics

2 answers:

Naddik [55]2 years ago

8 0

Answer: X1= 4, X2= 7

Step-by-step explanation:

sdas [7]2 years ago

4 0

You find values of 28 that add to -11! in this case thats -7 and -4. after that just plug in (x-7)(x-4)=0 so: x=4, x=7

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If x=9 and y=−3, evaluate the following expression:4/x−yGive your answer as a fraction in its simplest form.

qwelly [4]

Answer:1/3
4/9-(-3)=4/12=
1/3

6 0

3 years ago

Read 2 more answers

What is the volume of a sphere if it has a radius of 3 centimeters? (Use 3.14 for TT.)

snow_tiger [21]

Answer:

9.52

Step-by-step explanation:

4 0

3 years ago

This is math, help me with it plz

dangina [55]

Answer: X=136 degrees
Explanation: A triangle has a total of 180 degrees measuring all 3 angles. 180-90-46 gives me 44 left, then subtract 44 from 180 and that gives you 136 degrees.

3 0

3 years ago

Hiii! can someone please help me with my maths question

beks73 [17]

Step-by-step explanation:

a^2 + b^2 = c^2

(x+2)^2 + 4x^2 = (3x+4)^2

(x+2)(x+2)+ 4x^2= (3x+4)(3x+4)

x^2 + 2x + 2x + 4 + 4x^2 = 9x^2 + 12x + 12 x + 16

5x^2 + 4x + 4 = 9x^2 + 24x + 16

-4x^2 - 20x - 12 = 0

now we can use the quadratic formula

(-b±√(b²-4ac))/(2a)

I can't type all this so

.....

x = -0.697224362 or -4.302775638

AB can't be negative so it's the first one

so it's equals to 1.302775638

6 0

3 years ago

How many 5-member chess teams can be chosen from 15 interested players? Consider only the members selected, not their board posi

ryzh [129]

<u>Answer</u>:

3003 number of 5-member chess teams can be chosen from 15 interested players.

<u>Step-by-step explanation:</u>

Given:

Number of the interested players = 15

To Find:

Number of 5-member chess teams that can be chosen = ?

Solution:

Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations, we will use the formula $nCr = \frac{n!}{r!(n - r)!}$

where

n represents the total number of items,

r represents the number of items being chosen at a time.

Now we have n = 15 and r = 5

Substituting the values,

$15C_5 = \frac{15!}{5!(15- 5)!}$

$15C_5 = \frac{15!}{5!(10)!}$

$15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 }{5 \times 4 \times 3 \times 2 \times 1(10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1)}$

$15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11}{(5 \times 4 \times 3 \times 2 \times 1)}$

$15C_5 = \frac{360360}{120}$

$15C_5 = 3003$

7 0

3 years ago