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Veronika [31]
3 years ago
14

What is the minimum number of times you must throw three fair six-sided dice to ensure that the same sum is rolled twice?

Mathematics
1 answer:
Vladimir [108]3 years ago
4 0
For three fair six-sided dice, the possible sum of the faces rolled can be any digit from 3 to 18.
For instance the minimum sum occurs when all three dices shows 1 (i.e. 1 + 1 + 1 = 3) and the maximum sum occurs when all three dces shows 6 (i.e. 6 + 6 + 6 = 18).

Thus, there are 16 possible sums when three six-sided dice are rolled.

Therefore, from the pigeonhole principle, <span>the minimum number of times you must throw three fair six-sided dice to ensure that the same sum is rolled twice is 16 + 1 = 17 times.

The pigeonhole principle states that </span><span>if n items are put into m containers, with n > m > 0, then at least one container must contain more than one item.

That is for our case, given that there are 16 possible sums when three six-sided dice is rolled, for there to be two same sums, the number of sums will be greater than 16 and the minimum number greater than 16 is 17.
</span>
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Answer:

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Step-by-step explanation:

El enunciado es incorrecto, su forma correcta es: <em>En una escuela hay 196 estudiantes, de los cuales 84 son mujeres. La razón geométrica de mujeres a varones que estudian en dicha escuela es:</em>

Es sabido que la especie humana solo tiene dos formas en un sentido biológico: hombre y mujer. Si 84 de los 196 estudiantes son mujeres, entonces 112 son hombres. En consecuencia, la razón geométrica de mujeres a varones es de 3 mujeres por cada 4 hombres.

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Round 2769.44 to the nearest tenths place
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2769.44
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Which point is located at (-5,5)​
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Step-by-step explanation:

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Two points located on jk are j (-1,-9) and k (5,3). What is the slope of jk?
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Answer:

2

Step-by-step explanation:

slope of line= \frac{y1 - y2}{x1 - x2}

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=  \frac{3 - ( - 9)}{5 - ( - 1)}  \\  =  \frac{3 + 9}{5 + 1}  \\  =  \frac{12}{6}  \\  = 2

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3 years ago
Read 2 more answers
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