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stealth61 [152]
4 years ago
5

Which of the substances in the chemical equation is a pure substance?

Chemistry
2 answers:
Anni [7]4 years ago
7 0

Answer:

D. all of these

Explanation:

GarryVolchara [31]4 years ago
7 0
The answer is D. All of these. Hope this helps. You're welcome sis
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Organic compounds are distinguished by molecules that contain ________ bonded to other elements.
fredd [130]
The answer is carbon
6 0
3 years ago
Wedges and dashes are used to indicate the ____________ shape in a drawn structure. A wedge indicates that the atom or group is
OverLord2011 [107]

Answer:

Wedges and dashes are used to indicate the three dimensional shape in a drawn structure.

A wedge indicates that the atom or group is GOING OUT of the page.

Explanation:

wedges and dashes are ways or drawings use to represent three dimensional shape in a structure. Lines are use to represent image in the structure. A wedge line shows that molecules or bonds are moving towards the viewer i.e out of the the page.

A dashes line shows that bonds or atom are moving away the viewer or going into the group.

4 0
3 years ago
During a laboratory experiment, you discover that an enzyme-catalyzed reaction has a ∆g of -100 kcal/mol. if you double the amou
Debora [2.8K]

The doubling the amount will change the gibbs free energy as it is an extensive property which depends upon the the amount of the substance


However as asked in question the DeltaG has unit of kcal /mol

So we have already defined the amount of substance to be one mole this means the value per mole will be same irrespective of the amount taken as we are reporting it for a fixed one mole of a substance

Hence answer is

-100 kcal/mol


4 0
3 years ago
Read 2 more answers
Silver chloride, AgCl (Ksp = 1.8 x 10‒10), can be dissolved in solutions containing ammonia due to the formation of the soluble
Sergeeva-Olga [200]

Explanation:

The given reaction will be as follows.

           AgCl(s) \rightarrow Ag^{+}(aq) + Cl^{-}(aq) ............. (1)

     K_{sp} = [Ag^{+}][Cl^{-}] = 1.8 \times 10^{-10}

Reaction for the complex formation is as follows.

          Ag^{+}(aq) + 2NH_{3}(aq) \rightleftharpoons [Ag(NH_{3})_{2}]^{+}(aq) ........... (2)

          K_{f} = \frac{[Ag(NH_{3})_{2}]}{[Ag^{+}][NH_{3}]^{2}} = 1.0 \times 10^{8}

When we add both equations (1) and (2) then the resultant equation is as follows.

             AgCl(s) + 2NH_{3}(aq) \rightarrow [Ag(NH_{3})_{2}]^{+}(aq) + Cl^{-}(aq) ............. (3)

Therefore, equilibrium constant will be as follows.

                       K = K_{f} \times K_{sp}

                          = 1.0 \times 10^{8} \times 1.8 \times 10^{-10}

                          = 1.8 \times 10^{-2}

Since, we need 0.010 mol of AgCl to be soluble in 1 liter of solution after after addition of NH_{3} for complexation. This means we have to set

               [Ag^{+}] = [Cl^{-}]

                          = \frac{0.010 mol}{1 L}

                          = 0.010 M

For the net reaction, AgCl(s) + 2NH_{3}(aq) \rightarrow [Ag(NH_{3})_{2}]^{+}(aq) + Cl^{-}(aq)

Initial :                             0.010         x                     0                           0

Change :                    -0.010         -0.020             +0.010                +0.010

Equilibrium :                   0            x - 0.020           0.010                 0.010

Hence, the equilibrium constant expression for this is as follows.

              K = \frac{[Ag(NH_{3})^{+}_{2}][Cl^{-}]}{[NH_{3}]^{2}}

     1.8 \times 10^{-2} = \frac{0.010 \times 0.010}{(x - 0.020)^{2}}

             x = 0.0945 mol      

or,          x = 0.095 mol (approx)

Thus, we can conclude that the number of moles of NH_{3} needed to be added is 0.095 mol.

3 0
4 years ago
Each elements on the periodic chart is made up of a certain kind of atom. argree or disagree reason why
Katena32 [7]
Agree cuz its one elemet
8 0
3 years ago
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