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andriy [413]
3 years ago
11

HELP plz I need it right now

Mathematics
1 answer:
nlexa [21]3 years ago
7 0
Https://us-static.z-dn.net/files/d43/8774a5c2c75c2320f2c27ccdcacd8dd5.jpg

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WARRIOR [948]
10 is the correct answer
4 0
2 years ago
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List at least two advantages each of using a credit card and using cash.
Sonbull [250]
Credit Cards: You don't have to worry about how much cash you have at hand. You can get money when you need it.

Money: You won't overspend. You won't have to worry about fees.
5 0
3 years ago
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A dose of a new pharmaceutical drug is decaying according to the half-life model f(t) = Ne-0.2174, where N is the dose
Rudiy27

Answer:

  14.7

Step-by-step explanation:

Perhaps your equation is ...

  f(t) = N·e^(-0.2174t)

We want f(6) = 4, so ...

  4 = N·e^(-0.2174·6) = N·e^-1.3044 ≈ 0.2713N

  N = 4/0.2713 = 14.7 . . . . milligrams

The dose amount was about 14.7 mg.

6 0
3 years ago
Robert is lying on the ground, looking at the top of a flagpole. The angle of elevation to the top of the flagpole is
NeTakaya

Answer:

Height of flagpole = 571 ft

Step-by-step explanation:

Given:

Angle of elevation to the top of the flagpole is 55° .

Distance from the eyes to the base of flagpole = 400 ft.

To find the height of the flagpole.

Solution:

We can draw the situation as a right triangle as shown below.

In triangle ABC.

BC=400\ ft

∠C= 55°

To find the length AB (height of the flagpole).

Applying trigonometric ratio :

\tan\theta=\frac{Opposite\ side}{Adjacent\ side}

\tan C=\frac{AB}{BC}

Plugging in values.

\tan 55\°=\frac{AB}{400}

Multiplying both sides by 400.

400\tan 55\°=\frac{AB}{400}\times 400

571.26=AB

∴ AB\approx 571\ ft

Height of flagpole = 571 ft

6 0
3 years ago
6x(x − 4) − 16x2 − (9x − 1)?
krek1111 [17]

Answer:

\large\boxed{A.\ -10x^2-33x+1}

Step-by-step explanation:

6x(x-4)-16x^2-(9x-1)\qquad\text{use the distributive property}\\\\=(6x)(x)+(6x)(-4)-16x^2-9x-(-1)\\\\=6x^2-24x-16x^2-9x+1\qquad\text{combine like terms}\\\\=(6x^2-16x^2)+(-24x-9x)+1\\\\=-10x^2-33x+1

7 0
3 years ago
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