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4 years ago

7

Quickly! Giving brainliest to the CORRECT answer.

1 answer:

maw [93]4 years ago

3 0

Answer:11 bikers

Step-by-step explanation:

560 ➗ 50=11.2

Approximate to 1dp is 11

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Help me with school (math)!!!

Oliga [24]

Answer: y=-4x+7

Step-by-step explanation: Move 8x to the right side to isolate y. 2y=14-8x. Divide the whole equation by 2 to get y by itself. y=7-4x

6 0

2 years ago

You were watching a one hour and 30 min movie, and then you got up and went to the bathroom, when you came back, there was only

kiruha [24]

Answer:

56 minutes

Step-by-step explanation:

90-34=56

If it says how long you spent in the bathroom, that should be factored in as well, in which case the answer would be 90-34-(time spent in the bathroom = your answer

8 0

3 years ago

Read 2 more answers

olganol [36]

Answer:

the possible coordinates are -9 and 3

Step-by-step explanation:

coordinates of B=(x2,y2)= (5,1)

Coordinates of A= (x1, y1)= (-3, z)

distance= 10 units

Formula: d= $\sqrt{(y2-y1)^2+(x2-x1)^2}$

substituting the values in the above formula

10= $\sqrt{(z-(-3))^2+(-3-5)^2}$

10= $\sqrt{(z+3)^2+(-8)^2}$

10= $\sqrt{(z^2 +6z+9)+(64)}$

10= $\sqrt{(z^2 +6z+73)}$

taking square root on both sides

100= $z^2 +6z+73$

100-73= $z^2 +6z$

$z^2 +6z-27$ =0

$z^2 +9z-3z-27=0$

$z(z+9) -3(z+9)=0$

$(z-3)(z+9)=0\\z-3=0 ; z+9=0\\z=3 : z=-9$

3 0

2 years ago

Please help I'm trying to figure out 4-15 but i don't know how to.

ivann1987 [24]

I believe it’s 80 I have to redo this like 3 times

7 0

3 years ago

Read 2 more answers

* Some amount of billiard balls were arranged in an equilateral triangle. And 5 balls were extra. When the same set of billiard

Agata [3.3K]

Lets say billiard balls are arranged in rows to form an equilateral triangle, then the first row consists of 1 ball, second row consists of 2 balls, and third row consists of 3 balls, and so on. So there must be $n$ balls in the $n^{th}$ row.

So, the total number of balls that forms the equilateral triangle with $n$ rows is:

$1+2+3+4+5+....+n=\frac{n(n+1)}{2}$

Let $x_1$ and $x_2$ be the total number of balls in the first and second arrangements respectively.

Then,

$x_1=\frac{n(n+1)}{2} +5$

It has been said that there were 11 lesser balls in the second arrangement:

$x_2=\frac{1+(n+1)}{2} \times (n+1)-11=(n+1) \times \frac{(n+2)}{2} -11$

Since, $x_1=x_2$

$\frac{(n+1)}{2} \times n+5=\frac{(n+2)}{2} \times(n+1)-11$

multiplying both the sides by 2

$(n+1)\times n+10=(n+2)(n+1)-22$

$n+n^2=n^2+n+2n+2-22-10$

$2n=22+10-2$

$2n=30$

$n=15$

Therefore,

$x_1=\frac{(n+1)}{2}\times n+5=\frac{15+1}{2} \times 15+5=125$

So, there were 125 balls at the set.

4 0

3 years ago

Read 2 more answers