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Debora [2.8K]
3 years ago
12

What is the equation in slope intercept form of the perpendicular bisector of the given line segment?

Mathematics
1 answer:
andreev551 [17]3 years ago
6 0

Answer:

y = -4x - 6

Step-by-step explanation:

The equation of a line in point-slope form.

y - y_1 = m(x - x_1)

is the equation of the line containing point (x1, y1) and having slope, m.

The given point of the perpendicular bisector is (-1, -2), so in this case, x1 = -1, and y1 = -2.

We need the slope of the perpendicular bisector. First we find the slope of the segment. We start at point (-5, -3). We go up 1 unit and 4 units to the right, and we are at another point on the segment. Since slope = rise/run, the slope of the segment is 1/4. The slopes of perpendicular lines are negative reciprocals, so the slope of the perpendicular bisector is the negative reciprocal of 1/4, so for the perpendicular bisector, m = -4.

Now we use the equation above and our values.

y - y_1 = m(x - x_1)

y - (-2) = -4(x - (-1))

y + 2 = -4(x + 1)

y + 2 = -4x - 4

y = -4x - 6

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Answer:

Step-by-step explanation:

3 0
3 years ago
The exchange rate at a post office is £1 = 1.17 euros <br><br> how many euros will u get for £280
Sati [7]

Answer:

327.6 €

Step-by-step explanation:

you can solve with an equation

1£ : 1.17€ = 280£ : x

1 : 1.17 = 280 : x

x = 1.17 * 280 : 1

x = 327.6

-------------------

check

1 : 1.17 = 280 : 327.6

0.85 = 0.85

the answer is good

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or you can simpy solve with a multiplication

280 * 1.17 = 327.6

8 0
3 years ago
If two polynomial equations have real solutions, then will the equation that is the result of adding, subtracting, or multiplyin
kirill115 [55]

No. A polynomial equation in one variablel ooks like P(x) = Q(x), where P and Q are polynomials.

Consider polynomial equations x^2 = 3 and x^2 = 1.

Obviously they have real solutions.

Subtract the two polynomial equations:

(x^2 - x^2) = (3 - 1)

0 = 2...

We get the polynomial equation 0 = 2. We call this a polynomial equation because single constants are also by definition polynomials.

Obviously 0 = 2 has no real solution.

3 0
2 years ago
A farmer was counting his chickens and pigs. He had 16 animals in all and counted 54 legs. How many chickens does he have
Vikentia [17]

Answer:

5 chickens

Step-by-step explanation:

Let's set chickens and pigs with variables "c" and "p" respectively.

We know there a 16 animals in all, so there are:

c+p=16

We know there are 54 legs and chickens have 2 legs and pigs have 4 legs each:

2c+4p=54

Now we have our system of equations:

c+p=16

2c+4p=54

We are trying to find the number of chickens, so we write the first equation in respect to c.

p=16-c

Substituting the first derived equation to equation two:

2c+64-4c=54

Simplifying:

64-2c=54

2c=10

c=5

So there are 5 chickens.

8 0
3 years ago
Select Translation, Reflection, or Rotation to identify the single transformation that transforms ∆PQR to ∆P'Q'R'.
Sergeeva-Olga [200]

Part A

Represents 'Reflection'. This is so because the y-coordinates of P, Q and R remain the same in P' , Q' and R', and only the x-coordinate changes. Hence, it is reflection along the y-axis

Part B

Represents 'Rotation'. Here, the x-coordinates and y-coordinates of each of the points have changed, and the figure has been rotated clockwise around the point Q by 90°

Part C

Represents a combination of 'Translation' and 'Reflection'. Here either of the two has happened:

  • First, all the points have been moved downwards by a fixed distance, thus changing the y-coordinate. Then, the resulting image has been reflected along the y-axis, thus changing the x-coordinate of all the points
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Part D

Represents 2 'Translations'. Here the image has been shifted by a fixed distance in both the downward direction and the right direction. Thus, it has resulted in change of both x and y coordinates.

8 0
3 years ago
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