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Mnenie [13.5K]
3 years ago
13

What is the square root of -1​

Mathematics
1 answer:
aalyn [17]3 years ago
7 0

Answer:

"i". There's no more than that. Its just "i".

Step-by-step explanation:

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The Cobb family’s natural gas bill was 85.50 for 95 cubic feet of gas, What is the unit rate? (Cost per cubic foot of gas?)
Ratling [72]

Answer:

I believe it would cost 9 cents per cubic foot of gas.

Step-by-step explanation:

7 0
3 years ago
A rectangular flower bed is five feet longer than it is wide. its area is eighty-four square feet.
777dan777 [17]
Lets say w is the width of the flower bed. We can make an equation to find the area.
The length of the of the flower bed is (w+5) and the width is w.
To find the area we need to multiply the length(w+5) by the width(w) and set it equal to 84,
(w+5)(w)=84
w^2 +5w=84
Using the quadratic equation you get the solutions of 7 and -12. Since 7 is positive it is our width. Our length is 7+5 or 12.
3 0
3 years ago
If you have 20 coins worth $1.35, and you only have nickels and dimes, how many do you have of each coin?
ankoles [38]
N + d = 20....n = 20 - d
0.05n + 0.10d = 1.35

0.05(20 - d) + 0.10n = 1.35
1 - 0.05d + 0.10d = 1.35
-0.05d + 0.10d = 1.35 - 1
0.05d = 0.35
d = 0.35/0.05
d = 7 <==== 7 dimes

n + d = 20
n + 7 = 20
n = 20 - 7
n = 13 <=== 13 nickels
5 0
3 years ago
Find the measure of an angle whose complement is five times its measure.
ch4aika [34]

Answer:

The measure of the unknown angle is 15°.

Step-by-step explanation:

Represent this angle by A.  Then the complement of A is 90° - A.

"Angle whose complement is five times its measure" would be expressed as

90° - A = 5A

Solve this for A by adding A to both sides:

90° = 6A.  Then A = 90°/6, or 15°

4 0
2 years ago
Find the sum of the infinite series 1/3+4/9+16/27+64/81+.... if it exists.
pshichka [43]
9/27, 12/27, 16/27

So this is a geometric sequence as each term is 4/3 the previous term.

Since the common ration is greater than one the sum of the series diverges, it does not exist.  (The sum just keeps getting larger and larger)

For a geometric series to have a sum r^2<1

So that the normal sum....

s(n)=a(1-r^n)/(1-r)   becomes if r^2<1

s=a/(1-r)
6 0
3 years ago
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