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expeople1 [14]
4 years ago
12

Yoga Fun charges a $63 starting fee plus $12 per class. Yoga For All charges no starting fee and $15 per class. For how many cla

sses will the cost be the same at both places?
Mathematics
1 answer:
Ainat [17]4 years ago
6 0

Answer:

Step-by-step explanation:

so the equation would be 63+12x=15x

now you would have to isolate the variables

63+ 12x= 15x

    -12x    -12x

leaving you

63 = 3x

21=x

Hoped that helped

If this is good plz mark me as brainliest

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Write the ratio as a fraction in simplest form with whole numbers in the numerator and denominator 16 cm to 20 cm
emmainna [20.7K]

Answer:

4/5

Step-by-step explanation:

16/20 in a simpler form is 8/10. 8/10 in the simplest form is 4/5 (division)

8 0
3 years ago
Read 2 more answers
In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank
fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) Amount \ of \, water \ remaining \ in \, the \ tank \ is \  \frac{x^3(6-\pi) }{6}

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The  volume of the sphere = \frac{4}{3} \pi r^3

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = \frac{4}{3} \pi \frac{x^3}{8}= \frac{1}{6} \pi x^3

For tank B

Volume of tank = x³

The  volume of the spheres = 8 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = 8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}

For tank C

Volume of tank = x³

The  volume of the spheres = 64 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = 64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The  volume of the spheres = 512 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = 512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}

Amount \ of \ water \, remaining \, in \, the \ tank =  \frac{x^3(6-\pi) }{6}.

5 0
3 years ago
The question is in the pic
Len [333]

Answer:

reflection on the y axis

Step-by-step explanation:

it flips from side to side

4 0
3 years ago
Free brainly for any1
Natali5045456 [20]

Answer:

Can I please get Brainly I really need it

Step-by-step explanation:

oh and thank you so much for the points, hope you have a good day :)

5 0
3 years ago
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13) A rectangular garden has an area of 45 square meters. The garden will be 4 meters longer than its width Write and sowe an eq
11Alexandr11 [23.1K]

Answer:

9m ×5m

Step-by-step explanation:

Area of a rectangle= length ×width

Let the width be W meters and the length be L meters.

2 equations can be written from the given information:

45= WL -----(1)

L= W +4 -----(2)

Substitute (2) into (1):

45= W(W +4)

<em>Expand:</em>

45= W² +4W

<em>-45 on both sides:</em>

W² +4W -45= 0

<em>Factorise:</em>

(W +9)(W -5)= 0

W+9=0 or W-5=0

W= -9 or W= 5

(reject)

Substitute W= 5 into (2):

L= 5 +4

L= 9

∴ The dimensions of the garden is 9m ×5m.

6 0
3 years ago
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