Therefore, f(x) = 2x + 3 is your derivative function, and you need to find the original curve. So find the antiderivative using the given conditions...
∫f(x) = ∫2x + 3 dx F(x) = x^2 + 3x + C 2 = (1)^2 + 3(1) + C 2 = 4 + C C= -2
Therefore, the curve is F(x) = x^2 + 3x - 2
Proof: The derivative is the slope at every (x, y) point. The derivative of F(x) comes out to be 2x + 3, so we have found the curve. Plug in x = 1, and y = 2, so the conditions have been met.
