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Slav-nsk [51]
10 months ago
6

A rectangle has length that is 5 less than 2 times the width. Write an expression for the area of the rectangle.

Mathematics
1 answer:
a_sh-v [17]10 months ago
7 0

We are given a relationship between the sides of a rectangle, that is, the length of one of its sides is 5 less two times its width, and we are asked to find an expression for the area. Let's remember that the area of a rectangle is equal to the product of the length of its side by its width. Let "w" be the length of the rectangle and "L" its lenght, then the area is given by the following formula:

A=Lw

We can use the relationship given in the problem, that is, its length being five less two times its width, that is:

L=5-2w

Replacing in the formula for the area we get:

A=(5-2w)w

Now we use the distributive law:

A=5w-2w^2

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jolli1 [7]

Answer:

See explanation

Step-by-step explanation:

<h3 /><h3>Step 1</h3>

Miguel wins $2 is if he pulls two chips with the number 1.  

<u>Probability of winning is: </u>

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<u> Probability of loosing is:</u>

  • 1- 1/6 = 5/6
<h3 /><h3>Step 2</h3>

<u>Missing values we found in the step 1, can be populated in the table:</u>

  • Xi === 2 === -1
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<u>Expected Value as per table data:</u>

  • 1/6*2 + 5/6*(-1) = -1/2

Expected value is $1/2 loss each time he plays

<h3 /><h3>Step 3</h3>

To make the game fair, the expected value should be zero.

<u>Then as per the calculation above, let's replace 2, with x, and find its value.</u>

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6 0
3 years ago
What is the area, in square units, of trapezoid ABCD shown below?
SOVA2 [1]

Given:

Trapezoid with bases 10 and 20, and height of the trapezoid is 6.

To find:

The area of the trapezoid.

Solution:

We know that the area of a trapezoid is:

A=\dfrac{1}{2}h(b_1+b_2)

Where, h is the height of the trapezoid and b_1,b_2 are bases of the trapezoid.

Putting h=6, b_1=10,b_2=20 in the above formula, we get

A=\dfrac{1}{2}(6)(10+20)

A=3(30)

A=90

The area of the trapezoid is 90 sq units. Therefore, the correct option is A.

7 0
2 years ago
Factor the GCF: 12a3b + 8a2b2 − 20ab3
Harrizon [31]
<span>12a^3b + 8a^2b^2 − 20ab^3

</span>12a^3b = 4ab(3a^2)
8a^2b^2 = 4ab(2ab)
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GCF = 4ab

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3 years ago
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Nata [24]

Answer: 5x-3y=44

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Standard form of equation of line = Ax+By=C

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Then, the equation of a line that passes through the points . (7, -3) and (4, -8) is given by -

(y-(-3))=\dfrac{-8-(-3)}{4-7}(x-7)

(y+3)=\dfrac{-8+3}{-3}(x-7)   [∵ (-)(-)=(+)]

(y+3)=\dfrac{-5}{-3}(x-7)

(y+3)=\dfrac{5}{3}(x-7)

3(y+3)=5(x-7)

3y+9=5x-35

9+35=5x-3y

44=5x-3y

Or 5x-3y=44

Hence, the required equation :-5x-3y=44

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3 years ago
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