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3 years ago

10

Marisa says 302×6=192 explain why Marisa's answer is not reasonable

1 answer:

cricket20 [7]3 years ago

8 0

She forgot the 0 in the middle, which is why she got 192. The correct answer is 1812

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I need help with this one

Zanzabum

Answer:

The coordinates of the midpoint of the two vertices are

(0,2) (Third option)

Step-by-step explanation:

<u>Coordinates Of A Midpoint </u>

Given a pair of points in the plane

$\displaystyle P_1\ (x_1,y_1)\ ,\ P_2(x_2,y_2)$

the coordinates of the midpoint of both points are

$\displaystyle x_m=\frac{x_1+x_2}{2}$

$\displaystyle y_m=\frac{y_1+y_2}{2}$

The vertices given in the figure are

$\displaystyle v_1(-4,1),\ v_2\ (4,3)$

So the x-coordinate of their midpoint is

$\displaystyle x_m=\frac{-4+4}{2}=\frac{0}{2}=0$

And the y-coordinate of their midpoint is

$\displaystyle y_m=\frac{1+3}{2}=\frac{4}{2}=2$

So the coordinates of the midpoint of the two vertices are

(0,2), the third option

6 0

3 years ago

10.The function f(x) is shown below:

velikii [3]

C
$f(x) = 5x - 14$

6 0

4 years ago

Read 2 more answers

What equation has the same solution as x^2-6x-14=0 ?

slavikrds [6]

<span>x^2-6x+-14=0 works out the same way</span>

5 0

3 years ago

A roller coaster starts with the cars being pulled up a ramp. The mass of the cars is estimated by the function m(p) = 175p + 1,

KiRa [710]

Answer:

$E(p)=51,450p+346,920$

Step-by-step explanation:

The function

$m(p) = 175p + 1,180$

gives the mass of the car as a function of the number of passengers in it.

And the function

$E(m) = 9.8m*h$

gives the potential energy of the car as a function of the car's mass.

Now if the height of the ramp is 30 meters, we have

$E(m) =9.8m*(30)$

$E(m) =294m$

And to find the potential energy as a function of the number of passengers, we just substitute $m(p)$ into $E(m)$ to get:

$E(m(p))=294(175p+1180)$

$\boxed{ E(p)=51,450p+346,920}$

which gives the potential energy as a function of the number of passengers.

7 0

4 years ago

Analyze the diagram below and complete the instructions that follow.

Trava [24]

Law of Cosines says

$b^2 = a^2 + c^2 - 2 ac \cos B$

$2 a c \cos B = a^2 + c^2 - b^2$

$\cos B = \dfrac{a^2 + c^2 - b^2}{2 a c}$

$\cos B = \dfrac{16^2 + 16^2 - 11^2}{2(16)(16)} = \dfrac{ 391}{512}$

$B = \arccos \dfrac{ 391}{512} \approx 40.2 ^\circ$

Choice C

5 0

3 years ago