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guajiro [1.7K]
3 years ago
5

4x-3y=17 Y=3x-4 Solve by subsition

Mathematics
1 answer:
Fudgin [204]3 years ago
8 0
4x - 3y = 17
y = 3x - 4
(-1, -7)
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The demand equation for a manufacturer's product is:
Juli2301 [7.4K]

From the given price function, we have;

(a) \frac{dp}{dq}  =  - 13

(b) The point elasticity of demand is 0.0256<u>;</u><u> </u><u>i</u><u>nelastic demand</u>

(c) $46.6

(d) Increase

<h3>How can the elasticity of demand be found?</h3>

a. The given function is presented as follows;

p = 50 \times (151 - q) ^{0.02 \times  \sqrt{q + 19} }

Differentiating the above function with a graphing calculator and setting q = 150 gives;

\frac{dp}{dq}  =  - 13

b. The point elasticity of demand is given by the formula;

e \:  = \frac{dq}{dp}  \times  \frac{p}{q}

When q = 150, we have;

P = 50

Which gives;

e \:  =  \frac{1}{13} \times  \frac{50}{150}  = 0.0256

The point elasticity of demand, <em>E </em>= <u>0.0256</u>

  • The <u>demand is inelastic</u> (less than 1) when the quantity demanded is 150 units

c. If the quantity demanded decreases from 150 to 140 units, we have;

0.0256 \:  =  \frac{1}{13} \times  \frac{p}{140}  =

Which gives;

p = 46.6

  • The price when the quantity demanded decreases to 140 is <u>$46.6</u>

d. Given that increase in price, from 46.6 to 50, increases the quantity demanded from 140 to 150, therefore;

  • The manufacturer should<u> increase the price</u>, <em>p </em>to increase the revenue, <em>R</em>.

R = p × q

Learn more about elasticity of demand here;

brainly.com/question/19141990

3 0
2 years ago
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