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ahrayia [7]
2 years ago
5

What is the length of side AB of the triangle?

Mathematics
2 answers:
oee [108]2 years ago
7 0
Start with the Pythagorean theorem{A²+B²=C², A and B are the sides and C is the Hypotenuse/Longest Side.}
2²+4²=C²
4+16=C²
20=C².....{now square root both sides.√}
√20=√C²
4.472= C

P.S.: hope I helped :)
Vikki [24]2 years ago
5 0

Answer:

the distance is 4.47 linear units

Step-by-step explanation:

Hello, I can help you with this.

you can solve this by using the distance between two points formula.

Step 1

let's remember the distance between two points formula.

Let

P1(x_{1},y_{1})\\P2(x_{2},y_{2})

the distance between P1 and P2 is given by:

d=\sqrt{(x_{2}-x_{1}) ^{2} +(y_{2}-y_{1}) ^{2}} \\

Step 2

all you have to do is put the values into the equation

Let

P1(2,1)

P2(4,5)

then

x_{1}=2\\y_{1}=1\\x_{2}=4\\y_{2}=5\\

d=\sqrt{(x_{2}-x_{1}) ^{2} +(y_{2}-y_{1}) ^{2}} \\\\d=\sqrt{(4-2) ^{2} +(5-1) ^{2}} \\\\d=\sqrt{(2) ^{2} +(4) ^{2}} \\\\d=\sqrt{20}\\ d=4.47

so the distance between A and B is 4.47

I hope it helps , have a great day.

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Find the degree of the monomial.<br><br> -1.75k2
HACTEHA [7]

Answer:

The degree of this monomial is 2.

Step-by-step explanation:

This is because the degree of a monomial (or a polynomial, binomial) is equal to the degree (exponent) of the term in the monomial. In polynomials, it would be the degree of the term with the HIGHEST degree.

-1.75k^2

The exponent is two, so the degree is two.

Hope this helped!!!

7 0
3 years ago
At what x value does the function given below have a hole?<br><br> f(x)=x+3/x2−9
S_A_V [24]

Answer:

hole at x=-3

Step-by-step explanation:

The hole is the discontinuity that exists after the fraction reduces. (Still doesn't exist for original of course)

The discontinuities for this expression is when the bottom is 0. x^2-9=0 when x=3 or x=-3 since squaring either and then subtracting 9 would lead to 0.

So anyways we have (x+3)/(x^2-9)

= (x+3)/((x-3)(x+3))

Now this equals 1/(x-3) with a hole at x=-3 since the x+3 factor was "cancelled" from the denominator.

4 0
2 years ago
Male and female high school students reported how many hours they worked each week in summer jobs. The data is represented in th
mihalych1998 [28]

Question:

1. The females worked less than the males, and the female median is close to Q1.

2. There is a high data value that causes the data set to be asymmetrical for the males.

3. There are significant outliers at the high ends of both the males and the females.

4. Both graphs have the required quartiles.

Answer:

The correct option is;

1. The females worked less than  the males, and the female median is close to Q1

Step-by-step explanation:

Based on the given data, we have;

For males

Minimum = 0

Q1 = 1

Median or Q2 = 20

Q3 = 25

Maximum = 50

For females;

Minimum = 0

Q1 = 5

Median or Q2 = 6

Q3 = 10

Maximum = 18

Therefore, the values of data that affect the statistical measures of spread and center are that

The females worked less than the males as such the statistical data for the females have less variability than the males in terms of interquartile range

Also the female median is very close to Q1, therefore it affects the definition of a measure of center.

5 0
3 years ago
Which answer is equal to 2sqrt-28?
Oksana_A [137]

2^2-28

=4-28

=-24

that is it

4 0
3 years ago
Huddson has practiced a 360-back flip for months. This week, he did it perfectly 24 out of 54 times. At this rate, how many time
iris [78.8K]
Let x = perfect flips out of nine
\frac{24}{54}  =  \frac{x}{9}
54x = 216
x = 4
4 flips
5 0
3 years ago
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