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polet [3.4K]
3 years ago
14

What is the C in C + 11 = 44?

Mathematics
1 answer:
vodka [1.7K]3 years ago
5 0
44-11=33
33+11=44
The answer is 33
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So what is a dilation and how will it effect the image and the preimage(i have 8th grade math).
Gennadij [26K]

Answer:

In geometry, a transformation is an operation that moves, flips, or changes a shape to create a new shape. A dilation is a type of transformation that enlarges or reduces a figure (called the preimage) to create a new figure (called the image).

Step-by-step explanation:

6 0
3 years ago
3x-4y+6=0 solve for y
DiKsa [7]

Answer: y=3/4x+3/2

Step-by-step explanation:

Let's solve for y.

3x−4y+6=0

Step 1: Add -3x to both sides.

3x−4y+6+−3x=0+−3x

−4y+6=−3x

Step 2: Add -6 to both sides.

−4y+6+−6=−3x+−6

−4y=−3x−6

Step 3: Divide both sides by -4.

−4y/−4= −3x−6/−4

y=3/4x+3/2

5 0
3 years ago
Need help with task! Show work if possible~~
Inessa [10]

Answer:

Please see attached picture for full solution.

Sorry, I'm not sure how to do Q7 :(

6 0
3 years ago
Can somebody help me on 23 and 24, it’s geometry
alexdok [17]

Answer:

  23.  x = 4; DE = 44

  24.  x = 25; DS = 28

Step-by-step explanation:

23. Point S is the midpoint of DE, so ...

  DS = SE

  3x +10 = 6x -2

  12 = 3x . . . . . . . . . add 2-3x

  4 = x . . . . . . . . . . . divide by 3

Then DS has length ...

  DS = 3x +10 = 12 +10 = 22

and DE is twice that length, so ...

  DE = 44

__

24. DS is half the length of DE, so is ...

  DS = DE/2 = 56/2

  DS = 28

Then x can be found from ...

  DS = x +3

  28 -3 = x = 25 . . . . . substitute value for DS

_____

<em>Comment on problem 24</em>

Sometimes it is easier to work parts of a problem out of sequence. Here, finding DS first makes finding x easier.

8 0
3 years ago
Read 2 more answers
Two accounts earn simple interest. The balance y (in dollars) of Account A after x years can be modeled by y=10x 500. Account B
12345 [234]
In an installment loan, a lender loans a borrower a principal amount P, on which the borrower will pay a yearly interest rate of i (as a fraction, e.g. a rate of 6% would correspond to i=0.06) for n years. The borrower pays a fixed amount M to the lender q times per year. At the end of the n years, the last payment by the borrower pays off the loan.

After k payments, the amount A still owed is

<span>A = P(1+[i/q])k - Mq([1+(i/q)]k-1)/i, = (P-Mq/i)(1+[i/q])k + Mq/i. </span>The amount of the fixed payment is determined by<span>M = Pi/[q(1-[1+(i/q)]-nq)]. </span>The amount of principal that can be paid off in n years is<span>P = M(1-[1+(i/q)]-nq)q/i. </span>The number of years needed to pay off the loan isn = -log(1-[Pi/(Mq)])/(q log[1+(i/q)]). The total amount paid by the borrower is Mnq, and the total amount of interest paid is<span>I = Mnq - P.</span>
3 0
3 years ago
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