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polet [3.4K]
3 years ago
14

What is the C in C + 11 = 44?

Mathematics
1 answer:
vodka [1.7K]3 years ago
5 0
44-11=33
33+11=44
The answer is 33
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Explain what is 90% of 180
Yakvenalex [24]

Answer:

The answer is 162.

Step-by-step explanation:

To find the percentage of a number:

Turn the percentage into a decimal. 90% to .90

Multiply the decimal by the number you want to find the percentage of. .90 x 180

The answer is the product.

4 0
3 years ago
Find the value of x.
prohojiy [21]
X would be 90° ... every x is 90°
3 0
3 years ago
According to the Holy Bible, Jesus begins to perform healings. There were many healers during Jesus’ time. What made Jesus’ heal
Gekata [30.6K]

Healing was essential to the ministry of Jesus because He envisioned healing as a physical symbol of forgiveness. He guaranteed the ultimate glory of the human body through His personal resurrection, but forecast that restoration by healing twisted, shrunken, blinded limbs and organs. The paralytic's restoration is but one of many such examples (Mark 2:1-12).

Though there were many healers, Jesus was able to even raise up the dead, and also there was one instance where the Canaanite woman struggled through His disciples' desire to dismiss her, and His own initial, courteous refusal, to get what she knew she could trust Him to grant (Matthew 16:28). The crowds "begged him to let the sick just touch the edge of his cloak," (Matthew 14:36), for "all who touched him were healed."

Healers were not able to do that, and Jesus also claimed that he was God's son, so performing miracles like this was like proving the point. Also, healers were not always able to heal the person, but Jesus was able to do so all the time (for free even!) so many people traveled to meet him so he could heal them.

The woman with a hemorrhage crept silently through the crowd to merely touch His clothes (Mark 5:28). She also claimed that she went to many healers, but she didn't get healed, in fact, she got worse! So that's an instance that proves the point.

<em>Thank you :D</em>

3 0
3 years ago
Help me simple this 42/90
igomit [66]
7/15 will be the most you can simplify
5 0
3 years ago
Read 2 more answers
A curve is given by y=(x-a)√(x-b) for x≥b, where a and b are constants, cuts the x axis at A where x=b+1. Show that the gradient
ankoles [38]

<u>Answer:</u>

A curve is given by y=(x-a)√(x-b) for x≥b. The gradient of the curve at A is 1.

<u>Solution:</u>

We need to show that the gradient of the curve at A is 1

Here given that ,

y=(x-a) \sqrt{(x-b)}  --- equation 1

Also, according to question at point A (b+1,0)

So curve at point A will, put the value of x and y

0=(b+1-a) \sqrt{(b+1-b)}

0=b+1-c --- equation 2

According to multiple rule of Differentiation,

y^{\prime}=u^{\prime} y+y^{\prime} u

so, we get

{u}^{\prime}=1

v^{\prime}=\frac{1}{2} \sqrt{(x-b)}

y^{\prime}=1 \times \sqrt{(x-b)}+(x-a) \times \frac{1}{2} \sqrt{(x-b)}

By putting value of point A and putting value of eq 2 we get

y^{\prime}=\sqrt{(b+1-b)}+(b+1-a) \times \frac{1}{2} \sqrt{(b+1-b)}

y^{\prime}=\frac{d y}{d x}=1

Hence proved that the gradient of the curve at A is 1.

7 0
3 years ago
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