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denis-greek [22]
3 years ago
13

Which distribution is likely to have a mean higher than the median?

Mathematics
1 answer:
qwelly [4]3 years ago
3 0

Answer:

A distribution that is skewed to the right is likely to have a mean higher than the median.

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I need the answers for those IMMEDIATELY ! Thank you!
Soloha48 [4]

Answer:

Hope this helped.

Step-by-step explanation:

2:x=2y+20  y=1/2x-10

4:x=4/5y+15/5 y=5/4x-4

6:x=-2y+10  y=-1/2x+5

8:x=-7/3y+100/3  y=-3/7x+100/7

4 0
3 years ago
Find the slope on the line
Alla [95]

Answer:

-1

Step-by-step explanation:

Use Rise/Run and since the line is negative the slope will be negative

8 0
2 years ago
The sum of three numbers is 104. The first number is 6 less than the second. The third number is 3 times the second. What are th
lara [203]
We can write this in math as x+y+z=104, x=y-6, and z=3y

Because we already know what x and z are in terms of y, we can substitute our values for x and z into the first equation. This now looks like (y-6) + y + (3y) = 104. Now we can simplify our equation to find our value for y.

y-6 + y + 3y = 104 simplifies to 5y - 6 = 104, then 5y=110, and finally y=22.

Now that we know our value for y we can find our values for x and z by substituting our value for y into the other two equations.

The second equation x = y-6 can be simplified as x = 22 - 6 and further simplified as x = 16.

The third equation z = 3y can be written as z = 3(22) or z = 66.

Our three numbers are 16, 22, and 66. Hope this helps you!
8 0
2 years ago
Calculate the distance between the points -11 and 4 on a number<br> line.
krek1111 [17]

Answer:

15, d

Step-by-step explanation:

The absolute value of |-11| + |4| is 11+4 which is 15

5 0
2 years ago
A town's population has been growing linearly. In 2003 the population was 47,000. The population has been growing by 1200 people
blsea [12.9K]

Answer:

Step-by-step explanation:

The population in 2003= 47000

Since the population increase by 1200 every year,

in 2004 the population will be 47000+1200

in 2005 the population will be 47000+(1200+1200) which is the same as

47000+2(1200) where 2 is 2 years after 2003,

Therefore the population x years after 2003 is 47000+x(1200).

P= 47000+1200x

b) The population at 2009 which is 6 years after 2003 will be

47000+(1200)*6=47000+7200= 54200

The population at 2009 is 54200,

7 0
2 years ago
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