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3 years ago

What is 5x - 20 + 2x -7

Mathematics

1 answer:

Marrrta [24]3 years ago

5 0

5x -20 + 2x -7
= 5x + 2x -20 -7
= 7x -27

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Match each area to its corresponding radius or diameter of the circle.(All areas are approximate.) )

MA_775_DIABLO [31]

Answer:

Radius: 12 units

Area: πr² = 3.14*12² = 452.16 square units

Diameter: 16.8 units

Area: πd²/4 = 3.14*16.8²/4 = 221.5584 square units

Radius: 3.4 units

Area: πr² = 3.14*3.4² = 452.16 square units

Diameter: 10 units

Area: πd²/4 = 3.14*10²/4 = 78.5 square units

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Quick anyone know this algebra 2 problem?

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3 years ago

The following set of coordinates most specifically represents which figure? (−5, 6), (−1, 8), (3, 6), (−1, 4) (6 points) Paralle

Vladimir [108]

Answer:

Rhombus

Step-by-step explanation:

The given points are A(−5, 6), B(−1, 8), C(3, 6), D(−1, 4).

We use the distance formula to find the length of AB.

$|AB|=\sqrt{(-1--5)^2+(8-6)^2}$

$|AB|=\sqrt{16+4}$

$|AB|=\sqrt{20}$

The length of AD is

$|AD|=\sqrt{(-1--5)^2+(6-4)^2}$

$|AD|=\sqrt{16+4}$

$|AD|=\sqrt{20}$

The length of BC is:

$|BC|=\sqrt{(-1-3)^2+(8-6)^2}$

$|BC|=\sqrt{16+4}$

$|BC|=\sqrt{20}$

The length of CD is

$|CD|=\sqrt{(-1-3)^2+(6-4)^2}$

$|CD|=\sqrt{16+4}$

$|CD|=\sqrt{20}$

Since all sides are congruent the quadrilateral could be a rhombus or a square.

Slope of AB $=\frac{8-6}{-1--5}=\frac{1}{2}$

Slope of BC $=\frac{8-6}{-1-3}=-\frac{1}{2}$

Since the slopes of the adjacent sides are not negative reciprocals of each other, the quadrilateral cannot be a square. It is a rhombus

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3 years ago

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Determine the quotient and the remainder in the division (4x^4 - 1 ) ÷ x + 1

EastWind [94]

(4x^4-1)÷x+1

(256x-1)÷x+1

256-1+1

256

The first step shows the problem

The second step powers 4x 4 times

The third step removes x

The 4th step shows the problem after x is removed.

The 5th step is the answer: 256

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3 years ago