Please attach the question
Answer:
(f-g)(x) = x^4 - x^3 - 4x^2 - 3
Step-by-step explanation:
(f-g)(x) = x^4 - x^2 + 9 - (x^3 + 3x^2 + 12)
(f-g)(x) = x^4 - x^2 + 9 - x^3 - 3x^2 - 12
(f-g)(x) = x^4 - x^3 - 4x^2 - 3
Answer:
40
Step-by-step explanation:
plug -8 into the x so
f(-8)=(-8)^2-3(8)=
=64-24=
=40
therefore, f(-8)=40
Answer:
Step-by-step explanation:
|3x+12|
one is as it is one is the negative value of it
3x + 12 - (3x + 12)
- 3x - 12
That is because both negative and positive values put in am absolute value become positive.