Find the component form of the vector v ⃗ with ‖v ⃗ ‖=4√3 when drawn in standard position v ⃗ lies in Quadrant II and makes a 30
° angle with the positive y-axis. Give exact values.
1 answer:
The answer:
first of all, we should know that the expression of a vector V (a, b) can be written as follow:
V = r (Vx i + Vyj), where r is the length of the vector, it is r = sqrt(V²x + V²y)
Vx is the component lying on the x-axis and Vy on the y-axis
<span>v ⃗ lies in Quadrant II, means Vx is less than 0 (negative)
</span>
so Vx= -r sin30° and Vy= rcos30°
r= <span>‖v ⃗ ‖=4√3
</span>
so we have v = - 4√3sin30° i + 4√3 cos30° j
the components are
v(- 4√3sin30°, 4√3 cos30°) = (-2√3, 4√3 cos30°)
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The box is 5m long, 3m wide, 4m high
Respuesta:
3,2 metros
Explicación paso a paso:
Área del trapecio:
A = 1/2 (a + b) h
h = altura; ayb son las bases
Área, A = 60
Sea una base más pequeña = a = 18;
b = 18 + 3/2 = 19,5
La altura se puede calcular así;
60 = 1/2 (18 + 19,5) h
60 * 2 = 37,5 horas
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h = 120 / 37,5
h = 3,2 metros