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3 years ago

Find the least common denominator for these two rational expressions

Mathematics

1 answer:

coldgirl [10]3 years ago

4 0

Answer: The LCD is 5y.

I hope this helps!

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Determine the equation of each line

katovenus [111]

Answer:

see explanation

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

(a)

here m = - $\frac{3}{4}$ and c = 6, hence

y = - $\frac{3}{4}$ x + 6 ← equation of line

(b)

here m = 6, hence

y = 6x + c ← is the partial equation

to find c substitute (2, - 6 ) into the partial equation

- 6 = 12 + c ⇒ c = - 6 - 12 = - 18

y = 6x - 18 ← equation of line

(c)

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (- 1, 3) and (x₂, y₂ ) = (4, 7)

m = $\frac{7-3}{4+1}$ = $\frac{4}{5}$ , hence

y = $\frac{4}{5}$ x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (- 1, 3 ), then

3 = - $\frac{4}{5}$ + c → c = 3 + $\frac{4}{5}$ = $\frac{19}{5}$

y = $\frac{4}{5}$ x + $\frac{19}{5}$ ← equation of line

3 0

3 years ago

In the sahara desert one day it was 146 degrees F .in the Gobi desert the temperature of - 54 degrees f was recorded what is the

ankoles [38]

Answer:

200

146- (-54)= 200

or use a number line

7 0

3 years ago

What is the absolute value of -5/8?

Gemiola [76]

well, -5/8 is -0.625.

the absolute value of -0.625 is 0.625.

and abs value of -5/8 is 5/8

7 0

3 years ago

Read 2 more answers

$5000 at a 5% interest for 3 1/2 years

larisa [96]

5,875 is the answer

4 0

3 years ago

Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of

Maru [420]

Parameterize $S{/tex] by[tex]\vec s(u,v)=u\,\vec\imath+v\,\vec\jmath+(8-u^2-v^2)\,\vec k$

with $0\le u\le1$ and $0\le v\le1$ .

Take the normal vector to $S$ to be

$\vec s_u\times\vec s_v=2u\,\vec\imath+2v\,\vec\jmath+\vec k$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_u\times\vec s_v)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^1\int_0^1(uv\,\vec\imath+v(8-u^2-v^2)\,\vec\jmath+u(8-u^2-v^2)\,\vec k)\cdot(2u\,\vec\imath+2v\,\vec\jmath+\vec k)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^1\int_0^1\bigg(2u^2v+(u+2v^2)(8-u^2-v^2)\bigg)\,\mathrm du\,\mathrm dv=\boxed{\frac{1553}{180}}$

6 0

3 years ago