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ANTONII [103]
3 years ago
7

The base of a prism are right triangles with leg lengths of 7 inches and 5 inches. the prism height is 12 inches. what is the vo

lume of the prism?
105 cubic inches
203 cubic inches
210 cubic inches
420 cubic inches

Mathematics
2 answers:
Wewaii [24]3 years ago
4 0
The volume formula is length x width x height. 7x5x12=420 cubic inches
Vladimir [108]3 years ago
4 0
The answer is 420 cubic in
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May you please help me. Do not Skip this Question. URGENT!
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Answer:

C

Step-by-step explanation:

The common ratio can be < 0

All that means is the entry's signs alternate.

For example

r = - 2

a = 3

Series = 3    -6    18     -54 etc. The members of the series become larger and larger in magnitude and the series diverges. It is not clear where it might stop.

-1 < r < 0 gives a much better behaved result.

The point is that c is incorrect.

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5.6 is the answer to this question
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Which equation matches the graph?
Vinvika [58]

Answer:

B

Step-by-step explanation:

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3 years ago
Read 2 more answers
At the beginning of the school year, the 7th grade class at Oak Hill Middle School has 480 students. There are 270 girls and 210
Dimas [21]

Answer:

Part 1: 43.75%

Part 2: 44.07%

Step-by-step explanation:

Hello!

(Pt.1) First, set up a ratio 210/480. Next, you use long division I got the percent 43.75. After that, you subtract 6 from the girls group, (because of them moving away and then more coming back.) and 2 from the boys group. Then, you subtract those from the school "population" and you get 472 as the final population. So then you set up another ratio, 208/472. I got a percent of 44.07% from that.

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7 0
2 years ago
Box all final answers. Little to no work will reccive little to no credit! I. (5 points) Let A and B be 4 x 4 matrices, with det
FinnZ [79.3K]

Answer: a) -6, b) 32, c) -48, d) 9, e) -12

Step-by-step explanation:

Since we have given that

A and B are 4 × 4 matrices.

Here,

det (A) = -3

det (B) = 2

We need to find the respective parts:

a) det (AB)

\mid AB\mid=\mid A\mid.\mid B\mid\\\\\mid AB\mid=-3\times 2=-6

b) det (B⁵ )

\mid B^5\mid=\mid B\mid ^5=2^5=32

c) det (2A)

Since we know that

\mid kA\mid =k^n\mid A\mid

so, it becomes,

\mid 2A\mid =2^4\mid A\mid=16\times -3=-48

d) \bold{det(A^TA)}

Since we know that

\mid A^T\mid=\mid A\mid

so, it becomes,

\mid A^TA\mid=\mid A^T\mid \times \mid A\mid=-3\times -3=9

e) det (B⁻¹AB)

As we know that

\mid B^{-1}\mid =\mid B\mid

so, it becomes,

\mid B^{-1}AB}\mid =\mid B^{-1}.\mid \mid A\mid.\mid B\mid=2\times -3\times 2=-12

Hence, a) -6, b) 32, c) -48, d) 9, e) -12

6 0
3 years ago
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