The number of bottles of soda purchased is 10 and the number of bottles of juice purchased is 4.
<u>Step-by-step explanation:</u>
Let us consider the soda bottles as x and juice bottles as y.
From the given data we can derive 2 equations,
35x+15y= 410. .....(1)
x=y+6. ....(2)
Substitute equation (2) in (1),
35(y+6)+15y=410.
35y+ 210+15y=410.
50y+210=410.
50y=410-210.
50y=200.
y=4.
Substitute y value in equation (2),
x=4+6.
x=10.
The number of bottles of soda purchased is 10 and the number of bottles of juice purchased is 4.
Answer:
James bought 11 good tickets and 5 bad tickets.
Step-by-step explanation:
Given that:
Cost of each good ticket = $8
Cost of each bad ticket = $5
Total amount spent = $113
Total tickets bought = 16
Let,
x be the number of good tickets bought
y be the number of bad tickets bought
x+y=16 Eqn 1
8x+5y=113 Eqn 2
Multiplying Eqn 1 by 5
5(x+y=16)
5x+5y=80 Eqn 3
Subtracting Eqn 3 from Eqn 2
(8x+5y)-(5x+5y)=113-80
8x+5y-5x-5y=33
3x=33
Dividing both sides by 3
Putting x=11 in Eqn 1
11+y=16
y=16-11
y=5
Hence,
James bought 11 good tickets and 5 bad tickets.
10.5, 11, 11.5, 12, 12.5...this is an arithmetic sequence with a common difference of 0.5
an = a1 + (n - 1) * d
n = term to find = 23
a1 = first term = 10.5
d = common difference = 0.5
sub and solve
a(23) = 10.5 + (23 - 1) * 0.5
a(23) = 10.5 + 22 * 0.5
a(23) = 10.5 + 11
a(23) = 21.5 <===
Answer:
x = 200
Step-by-step explanation:
Multiply by 4:
x + 120 + 2x = 720
3x = 600 . . . . . . collect terms, subtract 120
x = 200 . . . . . . . divide by 3
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<em>Check</em>
(200/4 +30) +(200/2) = 180
(50 +30) + 100 = 180
80 + 100 = 180 . . . . . true
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<em>Alternate solution</em>
If you like, you can simply work with the equation given.
(3/4)x + 30 = 180 . . . . collect terms
(3/4)x = 150 . . . . . . . . . subtract 30
x = 200 . . . . . . . . . . . . multiply by 4/3
