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antoniya [11.8K]
3 years ago
6

Please help asap!! Read carefully

Mathematics
1 answer:
ale4655 [162]3 years ago
7 0

Answer:

one x-intercept.

Transformation: shift to the right 8 units.

Step-by-step explanation:

The parent function is f(t)=t^{2}

To find the number of x-intercepts, we equate the function to zero.

\implies t^{2}=0

\implies t=0

There is only one x-intercept at t=0.

The transformed function is

g(t)=(t-8)^2

This function is obtained shifting the parent function 8 units to the right.

The x-intercept will now be at t=8.

Hence the image function also has one x-intercept.

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Can someone please help with this 7th grade math question?
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Answer:

B,,,,,,,,,  2, 6, 10, and -8

Step-by-step explanation:

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8 0
3 years ago
Can anybody help me with this ?
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f(x) = (3/4)ˣ - 4

As x gets really negative (3/4)ˣ grows positively without bound (because it's (4/3)⁻ˣ and 4/3 > 1).

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One number is 9 less than a second number. Their sum is -27. What is the first number?
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Answer:

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Step-by-step explanation:

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2 years ago
Write an equation for an ellipse centered at the origin, which has foci at (0,\pm\sqrt{63})(0,± 63 ​ )left parenthesis, 0, comma
steposvetlana [31]

Answer:

\frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }

Step-by-step explanation:

Since the foci are at(0,±c) = (0,±63) and vertices (0,±a) = (0,±91), the major axis is the y- axis. So, we have the equation in the form (with center at the origin) \frac{x^{2} }{b^{2} } + \frac{y^{2} }{a^{2} }.

We find the co-vertices b from b = ±√(a² - c²) where a = 91 and c = 63

b = ±√(a² - c²)

= ±√(91² - 63²)

= ±√(8281 - 3969)

= ±√4312

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So the equation is

\frac{x^{2} }{(14\sqrt{22}) ^{2} } + \frac{y^{2} }{91^{2} } = \frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }

8 0
3 years ago
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