Answer:
Step-by-step explanation:
Using the rule of exponents
![\sqrt[n]{a^{m} }](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5E%7Bm%7D%20%7D)
⇔ 
, then
![\sqrt[6]{7^{2} }](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7B7%5E%7B2%7D%20%7D)
= 
=
Answer:
This is your answer.. you add exponents
The ordered pair is included in the solution set to the following system is (0,2)
<h3>Set of inequalities</h3>
Given the set of inequalities
y > x2 + 1
y < x2 – x + 1
Equate both expressions to have:
x^2 + 1 = x^2 - x +1
1 = -x + 1
x = 0
Substitute x = 0 into any of the function
y = x^2 + 1
y = 1
This shows that the ordered pair is included in the solution set to the following system is (0,2)
Learn more on inequality here: brainly.com/question/24372553
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Because you're trying to make them congruent, equal the two expressions to each other.
So, for #10 you would equal them so it would look like this.
2x+2=5x-19
Then you would just go ahead and simplify
2x+2=5x-19
-2x -2x
---------------
2= 3x -19
+19 +19
---------------
21=3x
--- ----
3 3
x=7
This means that x should be 7. You can check this just by plugging it in
2x+2
2(7)+2 = 16
5x-19
5(7)-19= 16
Same with #11.
x+8=3x-14
-x -x
--------------
8=2x-14
+14 +14
--------------
22=2x
--- ----
2 2
x=11
Check.
x+8
11+8= 19
3x-14
3(11) - 14 = 19
Answer:
y = 
Step-by-step explanation:
Given
x(y + 2) = 3x + y ← distribute parenthesis on left side
xy + 2x = 3x + y ( subtract 2x from both sides )
xy = x + y ( subtract y from both sides )
xy - y = x ← factor out y from each term on the left side )
y(x - 1) = x ← divide both sides by (x - 1)
y =
