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3 years ago

[tex]\frac{3}{8} of 10x

Mathematics

1 answer:

pentagon [3]3 years ago

5 0

Answer: x = 3/80

Step-by-step explanation:

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A ball is launched upward at 14 m/s from a platform 30 m high.Find the maximum height the ball will reach and how long it will t

BartSMP [9]

Answer:

The ball will reach a maximum height of 39.993 meters after 1.428 seconds.

Step-by-step explanation:

Let suppose that no non-conservative forces acts on the ball during its motion, then we can determine the maximum height reached by the Principle of Energy Conservation, which states that:

$K_{1}+U_{g,1} = K_{2}+U_{g,2}$ (1)

Where:

$K_{1}$ , $K_{2}$ - Initial and final translational kinetic energies, measured in joules.

$U_{g,1}$ , $U_{g,2}$ - Initial and final gravitational potential energies, measured in joules.

By definition of translational kinetic energy and gravitational potential energy we expand and simplify the expression above:

$\frac{1}{2}\cdot m\cdot v_{2}^{2}+m\cdot g\cdot y_{2}= \frac{1}{2}\cdot m\cdot v_{1}^{2}+m\cdot g\cdot y_{1}$ (2)

Where:

$m$ - Mass of the ball, measured in kilograms.

$g$ - Gravitational acceleration, measured in meters per square second.

$v_{1}$ , $v_{2}$ - Initial and final speed of the ball, measured in meters per second.

$y_{1}$ , $y_{2}$ - Initial and final heights of the ball, measured in meters.

The final height of the ball is determined by the following formula:

$v_{2}^{2}+2\cdot g\cdot y_{2} = v_{1}^{2}+2\cdot g\cdot y_{1}$

$v_{1}^{2}-v_{2}^{2}+2\cdot g \cdot y_{1}=2\cdot g\cdot y_{2}$

$y_{2} = y_{1}+\frac{v_{1}^{2}-v_{2}^{2}}{2\cdot g}$ (3)

If we know that $y_{1} = 30\,m$ , $v_{1} = 14\,\frac{m}{s}$ , $v_{2} = 0\,\frac{m}{s}$ and $g = 9.807\,\frac{m}{s^{2}}$ , the maximum height that the ball will reach is:

$y_{2} = 30\,m + \frac{\left(14\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}}{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)}$

$y_{2} = 39.993\,m$

The ball will reach a maximum height of 39.993 meters.

Given the absence of non-conservative forces, the ball exhibits a free fall. The time needed for the ball to reach its maximum height is computed from the following kinematic formula:

$t = \frac{v_{2}-v_{1}}{-g}$ (4)

If we know that $v_{1} = 14\,\frac{m}{s}$ , $v_{2} = 0\,\frac{m}{s}$ and $g = 9.807\,\frac{m}{s^{2}}$ , then:

$t = \frac{0\,\frac{m}{s}-14\,\frac{m}{s} }{-9.807\,\frac{m}{s^{2}} }$

$t = 1.428\,s$

The ball will take 1.428 seconds to reach its maximum height.

6 0

3 years ago

Write the equivalent fraction, the reduced fraction, and the decimal equivalent for 45%. Jenny solved this problem and her work

Nadya [2.5K]

Answer:

Equivalent fraction: 45/100

Reduced fraction: 9/20

Decimal equivalent: 0.45

Step-by-step explanation:

Equivalent fraction: percentage is just out of 100. 45% is 45 out of 100, aka 45/100.

Reduced fraction is just simplifying both sides by the GCF. In this case, 5.

Decimal equivalent of a percentage is just dividing the numerator by the denominator, or taking the numerator or the percentage and placing the decimal point forward two digits.

6 0

3 years ago

Read 2 more answers

Select all of the number of ways in which a line and a circle can intersect.

dalvyx [7]

Answer:

0, 1, and 2

This is the answer

5 0

3 years ago

Read 2 more answers

Simplify (x − 4)(x2 + 3x − 1).

Korolek [52]

(x − 4)(x2 + 3x − 1)
=x^3 + 3x^2 - x -4x^2 - 12x +4
=x^3 -x^2 - 13x +4

answer is B.x^3-x^2-13x+4

4 0

3 years ago

In a casino on a Saturday, 90% of the visitors lost $100 each, 9% of the visitors lost $1,000 each, and the rest won $10,000 eac

liq [111]

x = total amount of visitors

so we have 90% that lost $100, 9% that lost $1000, now 90+9 = 99%, what's left is just 1% then, so 1% won $10,000.

Profit is Revenue - Cost.

so the profit for the casino, is not who wins, because from the wins the casino needs to pay that to the winner, so they're losing that much, so for the casino, profits is when a player loses, so their profit will come from the 99% that lost money then.

keeping in mind that

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em} \begin{array}{llll} \stackrel{\textit{90\% of x}}{\left( \cfrac{90}{100} \right)x}\implies 0.9x\qquad \stackrel{\textit{9\% of x}}{\left( \cfrac{9}{100} \right)x}\implies 0.09x \\\\\\ \stackrel{\textit{1\% of x}}{\left( \cfrac{1}{100} \right)x}\implies 0.01x \end{array}$

since we know that 90% lost $100, that means 0.9x(100) is the total amount lost by all of them, since we also know that 9% lost $1000, then 0.09x(1000) is the total amount lost by them, and the wins are of course just 0.01x(100000).

$\bf \stackrel{\textit{90\% at \$100}}{0.9x(100)}~~+~~\stackrel{\textit{9\% at \$1000}}{0.09x(1000)}~~-~~\stackrel{\textit{1\% at \$10000}}{0.01x(10000)}~~=~~\stackrel{\textit{casino's profit}}{80000} \\\\\\ 90x+90x-100x=80000\implies 80x=80000\\\\\\ x=\cfrac{80000}{80}\implies x=1000$

4 0

4 years ago