That would be the commutative property
Answer:
19
Step-by-step explanation:
you divide 266 by 14
Answer:
Step-by-step explanation:
{24a -18b}
=6 {4a-3b}
Answer:
a) (0.5256,0.5944)
c) Criticism is invalid
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 560
Proportion of mislabeled = 56%

a) 90% Confidence interval:


Putting the values, we get:

b) Interpretation of confidence interval:
We are 90% confident that the true proportion of all seafood in the country that is mislabeled or misidentified is between 0.5256 and 0.5944 that is 52.56% and 59.44%.
c) Validity of criticism
Conditions for validity:

Verification:

Both the conditions are satisfied. This, the criticism is invalid.
Answer:
<h3>6 feet</h3>
Step-by-step explanation
Using the pythagoras theorem;
Given
The length of the flag pole = 8 feet = opposite side
Length of the rope = 10 feet = hypotenuse
To determine how far out on the ground he need to secure the rope from the flagpole so that the rope is tight, we need to look for the adjacent. Using the equation
hyp² = opp² + adj²
10² = 8² + adj²
adj² = 100-64
adj² = 36
adj = √36
adj = 6feet
Hence the rope should be placed 6feet out of the ground