1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Reil [10]
3 years ago
8

Object a with a mass of 1.5 kilograms is moving with a velocity of 11.2 meters/second (moving in the x direction). it has a perf

ectly elastic collision with stationary object b that has a mass of 4.5 kilograms. after the collision, object b travels with a velocity of 5.6 meters/second. what is the final velocity for object a?
Physics
2 answers:
Masteriza [31]3 years ago
3 0
Conservation of momentum => momentum before collision = momentum after collision

Momentum before collision = momentum of object a = m*v = 1.5 kg * 11.2 m/s

= 16.8 N*s (in x direction)

Momentum after collision = momentum of object a + momentum of object b =

= 1.5 kg * v + 4.5 kg * 5.6m/s = 1.5kg*v + 25.2 N*s

= > 16.8 = 1.5v + 25.2 => 1.5v = 16.8 - 25.2 = -8.4

=> v = -8.4 / 1.5 = -5.6 m/s

The negative sign means that the object a went back after the collision.
MAVERICK [17]3 years ago
3 0

Answer:

-5.6

Explanation:

The one above me said the same thing but i found it a little bit confusing

You might be interested in
When acceleration and velocity are in opposing directions, the speed will​
melamori03 [73]

Answer:

If the velocity and acceleration are in the same direction (both have the same sign - both positive or both negative) the object is speeding up. If the velocity and acceleration are in opposite directions (they have opposite signs), the object is slowing down.

<h2>Please mark my answer brainliest for further answers :)</h2>

8 0
3 years ago
Read 2 more answers
Two 10-cm-diameter metal plates 1.0 cm apart are charged to {12.5 nC. They are suddenly connected together by a 0.224-mm- diamet
Alekssandra [29.7K]

Answer:

(a).The maximum current in the wire is 4.217\times10^{5}\ A.

(b). The electric field in the wire is 11.2\times10^{5}\ N/C.

(c).The current also decrease with time.

(d). The total amount of energy dissipated in the wire is 1.126\times10^{-5}\ J

Explanation:

Given that,

Diameter of metal plates = 10 cm

Distance between the plates = 1.0 cm

Charged = 12.5 nC

Diameter of copper wire = 0.224 mm

We need to calculate the cross section area of the plates

Using formula of area

A=\pi r^2

Put the value into the formula

A=\pi\times(5\times10^{-2})^2

A=7.85\times10^{-3}\ m^2

We need to calculate the capacitor

Using formula of capacitor

C=\dfrac{\epsilon_{0}A}{d}

Put the value into the formula

C=\dfrac{8.85\times10^{-12}\times7.85\times10^{-3}}{1.0\times10^{-2}}

C=6.94\times10^{-12}\ F

We need to calculate the resistance of the wire

Using formula of resistivity

R=\dfrac{\rho l}{A}

Put the value into the formula

R=\dfrac{1.7\times10^{-8}\times1.0\times10^{-2}}{\pi\times(0.1125\times10^{-3})^2}

R=4.27\times10^{-3}\ \Omega

We need to calculate the voltage

Using formula of charge

q=CV

V=\dfrac{q}{C}

Put the value into the formula

V=\dfrac{12.5\times10^{-9}}{6.94\times10^{-12}}

V=1.801\times10^{3}\ V

(a). We need to calculate the current

Using formula of current

I=\dfrac{V}{R}

I=\dfrac{1.801\times10^{3}}{4.27\times10^{-3}}

I=421779.85\ A

I=4.217\times10^{5}\ A

(b). We need to calculate the electric field

Using formula of electric field

E=\dfrac{kq}{r^2}

Put the value into the formula

E=\dfrac{9\times10^{9}\times12.5\times10^{-9}}{(1.0\times10^{-2})^2}

E=11.2\times10^{5}\ N/C

The electric field in the wire is 11.2\times10^{5}\ N/C.

(c). In this case, the voltage between the capacitor plates decreases as the charge decreases with time.

The current is directly proportional to the voltage between the plates .

Hence, The current also decrease with time.

(d). We need to calculate the total amount of energy dissipated in the wire

Using formula of energy

E=\dfrac{1}{2}CV^2

Put the value into the formula

E=\dfrac{1}{2}\times6.94\times10^{-12}\times(1.801\times10^{3})^2

E=1.126\times10^{-5}\ J

The total amount of energy dissipated in the wire is 1.126\times10^{-5}\ J

Hence, (a).The maximum current in the wire is 4.217\times10^{5}\ A.

(b). The electric field in the wire is 11.2\times10^{5}\ N/C.

(c).The current also decrease with time.

(d). The total amount of energy dissipated in the wire is 1.126\times10^{-5}\ J

8 0
3 years ago
Boyle's Law states that as the pressure on a gas increases at constant temperature the volume of the gas
elena55 [62]
Boyle’s law is P1V1 = P2V2. This shows that pressure and volume have an inverse relationship, so increase in pressure causes a decrease in volume. B is your answer
4 0
3 years ago
From class, weight is a measurement of the force of
Ahat [919]

Answer:

the answer is well known as gravity

7 0
3 years ago
How does water in a hot spring get hot?
OLEGan [10]
Water may come into contact with very hot rock heated by magma
4 0
2 years ago
Other questions:
  • Two spheres are 1.02 km apart. one of the spheres has a mass of 57.0 kg, and the force of attraction between the spheres is 1.79
    10·1 answer
  • Objects falling through the air experience a type of friction called air resistance. true or false
    8·2 answers
  • A stone with a mass of 0.70 kg is attached to one end of a string 0.80 m long. The string will break if its tension exceeds 65.0
    8·1 answer
  • A block slides on a frictionless surface. The block is given a 25 N force to the right and it accelerates at a rate of 3.5 m/s^2
    7·2 answers
  • HELP :). Explain how soaps lower the surface tension of the fats and oils ?
    5·1 answer
  • A small bead with a positive charge q is free to slide on a horizontal wire of length 4.5 cm . At the left end of the wire is a
    6·1 answer
  • Which of the atoms shown has an atomic number of 4?
    8·2 answers
  • Only 5 questions plz answer
    13·2 answers
  • A simple machine that operates using the principle of the screw is a-
    8·1 answer
  • E.) calculate the total heat required to change 10kg of ice at 0°c into water at 50°c. ​
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!