The air pressure inside the balloon is: 0.1432 Pa
The formulas and procedures that we will use to solve this problem are:
Where:
- a = area of the sphere
- r = radius
- π = mathematical constant
- P = Pressure
- F = Force
- a = surface area
Information about the problem:
- r = 5.0 m
- F = 45 N
- 1 Pa = N/m²
- 1 N = kg * m/s²
- a=?
- P=?
Using the formula of the sphere area we get:
a = 4 * π * r²
a = 4 * 3.1416 * (5.0 m)²
a = 314.16 m²
Applying the pressure formula we get:
P = F/a
P = 45 N/314.16 m²
P = 0.1432 Pa
<h3>What is pressure?</h3>
It is a physical quantity that expresses the force applied on the area of a surface.
Learn more about pressure at: brainly.com/question/26269477
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Answer:
h = 206.4 m
range = 515.9 m
Explanation:
from the question we are given the following:
initial velocity (u) = 75 m/s
angle above surface = 58 degrees
acceleration due to gravity (g) = 9.8 m/s^{2}
find the maximum height (h) and the horizontal distance
maximum height (h) = 
h = 
h = 206.4 m
the horizontal distance here is the range
range = 
range = 
range = 515.9 m
Answer:
73.13°
Explanation:
According to snell's law,
n1sinθi = n2sinθr
n1/n2 = sinθr/sinθi
Critical angle is the angle of incidence at the denser medium when the angle of incidence at the less dense medium is 90°
This means i=C and r = 90°
The Snell's law formula will become
n1/n2 = sinC/sin90°
n2/n1 = 1/sinC
Where n1 is the refractive index of the less dense medium = 1.473
n2 is the refractive index of the denser medium = 1.540
Substituting the values in the formula,
1.540/1.473 = 1/sinC
1.045 = 1/sinC
SinC = 1/1.045
SinC = 0.957
C = sin^-1(0.957)
C = 73.13°
d. none of the above
pressure affects volume not the other way round
Answer:
15 m
Explanation:
Given,
Mass ( m ) = 75 kg
Potential energy ( P.E ) = 11,025 J
To find : Hight ( h )
Formula : -
P.E = mgh
[ Note : The value of g = 9.8 m/s² ]
h = P.E / mg
= 11,025 / ( 75 x 9.8 )
= 11,025 / 735
h = 15 m
Hence,
15 m is the high off the ground must you be if you mass is 75 kg and you have 11,025 J of energy stored inside.
