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3 years ago

1. George Eliot pulls on a curtain string. If the curtain has a mass of 1.2 kg and she can pull

Physics

1 answer:

nekit [7.7K]3 years ago

6 0

Answer:

F = 4.8 N

Explanation:

Given that,

Mass of the curtain, m = 1.2 kg

Acceleration of the pull, a = 4 m/s²

We need to find the force she exerts on the curtain.

We know that,

F = ma

Put al the values,

F = 1.2 kg × 4 m/s²

= 4.8 N

So, the force is 4.8 N.

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A person in bare feet is standing under a tree during a thunderstorm, seeking shelter from the rain. A lightning strike hits the

Anni [7]

Answer:

$I=38.181\ A$ is the current through the body of the man.

$E=34.5\ J$ energy dissipated.

Explanation:

Given:

time for which the current lasted, $t=43\times 10^{-6}\ s$

potential difference between the feet, $V=21000\ V$

resistance between the feet, $R=550\ \Omega$

Now, from the Ohm's law we have:

$I=\frac{V}{R}$

$I=\frac{21000}{550}$

$I=38.181\ A$ is the current through the body of the man.

Energy dissipated in the body:

$E=I^2.R.t$

$E=38.181^2\times 550\times 43\times 10^{-6}$

$E=34.5\ J$

5 0

4 years ago

What happens to the speed of molecules as temperature increases

rusak2 [61]

Then the the speed of the molecules also increase

6 0

4 years ago

Read 2 more answers

Water flows through a first pipe of diameter 3 inches. If it is desired to use another pipe for the same flow rate such that the

Alborosie

Answer:

the diameter of the second pipe is 2.52 in

Explanation:

Given the data in the question;

We know that; the rate of flow is the same;

Av1 = Av2

v ∝ √h

$\frac{A1}{A2}$ = $\frac{V2}{V1}$

$\frac{A1}{A2}$ = √( $\frac{h2}{h1}$ )

( π/4.D1² / π/4.D2² ) = √( $\frac{h2}{h1}$ )

( D1² / D2² ) = √( $\frac{2h1}{h1}$ ) since second is double of first

( D1² / D2² ) = √( $\frac{2}{1}$ )

3² / D2² = √2

D2²√2 = 9

D2² = 9/√2

D2² = 9 / 1.4142

D2² = 6.364

D2 = √ 6.364

D2 = 2.52 in

Therefore, the diameter of the second pipe is 2.52 in

3 0

3 years ago

Taking test, need physics help ASAP please!

Neko [114]

Answer:

one free advice don't believe all this free advices give din brainly ok

5 0

3 years ago

Assuming the starting height is 0.0 m, calculate the potential energy of the cart after it has been elevated to a height of 0.5

Bogdan [553]

The potential energy is most often referred to as the "energy at rest" and is dependent on the elevation of an object. This can be calculated through the equation,

E = mgh

where E is the potential energy, m is the mass, g is the acceleration due to gravity, and h is the height. In this item, we are not given with the mass of the cart so we assume it to be m. The force is therefore,

E = m(9.8 m/s²)(0.5 m) = 4.9m

Hence, the potential energy is equal to 4.9m.

8 0

4 years ago