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Svetlanka [38]
3 years ago
11

Identify the domain of a radical function with an odd index.

Mathematics
1 answer:
Sonja [21]3 years ago
8 0

Answer:When n is an odd number, \sqrt[n]{a} is a real number for all values of a. Then, the domain is the real domain.

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find the value of tan (a-b) if cos a=4/5 on the interval (270, 360) and sin b=-5/13 on the interval (270, 360)
Rudiy27

We can find a and b using inverse trig functions,

\cos(a)=\frac{4}{5}\implies a=\arccos\Big(\frac{4}{5}\Big)\approx36.87 \\\sin(b)=-\frac{5}{13}\implies b=\arcsin\Big(-\frac{5}{13}\Big)\approx-22.62

\tan(36.87-(-22.62))\approx1.7

Hope this helps.

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3 years ago
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Answer:

= 3b/4

Step-by-step explanation:

= b . 4/12 + b . 3/12 + b . 2/12

Apply the fraction rule: a/c + b/c = a + b/c

= b . 4 + b . 3 + b . 2/12

= 4b + 3b + 2b/12

Add similar elements: 4b + 3b + 2b = 9b

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Cancel 9b/12: 3b/4

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-9

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