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wel
3 years ago
5

At which x-value does the cosine function attain a maximum value?

Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
7 0

9514 1404 393

Answer:

  x = 0

Step-by-step explanation:

It can help to keep a graph of the cosine function in mind. It starts off at its maximum value at x = 0.

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Answer:

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y=6^x-2

Step-by-step explanation:

Start with the parent function, a^x. The graph looks like it has been translated b units down, so our function is a^x+b. Now at x=0, y=-2. So b=-2. Next at x=1, y=3. 3=a^(1)-2, a=6. y=6^x-2 is the equation

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What is the radian measure for an angle that measures 720 degrees?
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Step-by-step explanation:

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Now, the value of 720 degrees can be calculated by multiplying the unit value and 720. So,

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PLEASE HELP Which expression represents the difference quotient of the function f (x) = negative StartRoot 2 x EndRoot?
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Answer:

c is the correct option

Step-by-step explanation:

from,

f'(x) = h >0 <u>f</u><u>(</u><u>x</u><u> </u><u>+</u><u> </u><u>h</u><u>)</u><u> </u><u>-</u><u> </u><u>f</u><u>(</u><u>x</u><u>)</u><u> </u>

h

f(x) = - √2x

f(x + h) = - √(2x + h)

f'(x) = h>0 <u>-</u><u>√(2x + h) - √2x</u>

h

rationalize the denominator

= h>0 <u>-</u><u>√</u><u>(</u><u>2</u><u>x</u><u> </u><u>+</u><u> </u><u>h</u><u>)</u><u> </u><u>+</u><u> </u><u>√</u><u>2</u><u>x</u><u> </u><u> </u><u>(</u><u>-</u><u>√</u><u>(</u><u>2</u><u>x</u><u> </u><u>+</u><u> </u><u>h</u><u>)</u><u> </u><u>-</u><u> </u><u>√</u><u>2</u><u>x</u><u>)</u>

h (-√(2x + h) - √2x)

= h>0 <u>4</u><u>x</u><u> </u><u>+</u><u> </u><u>2</u><u>h</u><u> </u><u>-</u><u> </u><u>4</u><u>x</u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>

h(-√(2x + h) -√2x)

= h>0 <u>2</u><u>h</u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>

h(-√(2x+h) - √2x)

= h>0 <u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>2</u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>

-√(2x+h) - √2x

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Hello,


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